Modern Methods in Elementary GeometryMacmillan, 1868 - 112 σελίδες |
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Αποτελέσματα 1 - 5 από τα 7.
Σελίδα 2
... direction it has passed over two right angles . When OB again coincides with OA , it has passed over four right angles . The minute - hand of a watch passes over four right angles in an hour . All right angles are equal , and the space ...
... direction it has passed over two right angles . When OB again coincides with OA , it has passed over four right angles . The minute - hand of a watch passes over four right angles in an hour . All right angles are equal , and the space ...
Σελίδα 4
... direction . Therefore DB is in the same straight line with AB . NOTE . When two angles are together equal to two right angles , either of these angles is called the supplement of the other . THEOREM II . If two straight lines AB , CD ...
... direction . Therefore DB is in the same straight line with AB . NOTE . When two angles are together equal to two right angles , either of these angles is called the supplement of the other . THEOREM II . If two straight lines AB , CD ...
Σελίδα 7
... direction of DF . And since DE = DF , the point E will coincide with A the point F. Therefore AE will coincide with AF , and must be equal to it . B E D F 3 COR . 1. The angle AED will coincide with the angle AFD and must be equal to it ...
... direction of DF . And since DE = DF , the point E will coincide with A the point F. Therefore AE will coincide with AF , and must be equal to it . B E D F 3 COR . 1. The angle AED will coincide with the angle AFD and must be equal to it ...
Σελίδα 15
... with B ' . And , because the angle B = the angle B ' , BC will take the direction of B'C ' . And , because BC = B'C ' , ' the point C will coincide with the point C ' . Therefore CA must coincide with C'A ' , and be THE STRAIGHT LINE . 15.
... with B ' . And , because the angle B = the angle B ' , BC will take the direction of B'C ' . And , because BC = B'C ' , ' the point C will coincide with the point C ' . Therefore CA must coincide with C'A ' , and be THE STRAIGHT LINE . 15.
Σελίδα 16
... direction of B'C ' . Then , since BC = B'C ' , C must coincide with C ' . Now , since BB ' , BA must take the direction of B'A ' , and the point A must lie somewhere on B'A ' . Also , since C = C ' , CA must 16 ELEMENTARY GEOMETRY .
... direction of B'C ' . Then , since BC = B'C ' , C must coincide with C ' . Now , since BB ' , BA must take the direction of B'A ' , and the point A must lie somewhere on B'A ' . Also , since C = C ' , CA must 16 ELEMENTARY GEOMETRY .
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A'BC Algebra alternate angle altitude angle equal arc CD ARITHMETIC BC² bisect BROOKE FOSS WESTCOTT CA² Cambridge centre chord circle touching circumference cloth coincide congruent CONIC SECTIONS contain convex angle convex polygon Crown 8vo diagonals diameter dicular divide Edward Thring ELEMENTARY TREATISE equal angles equally distant equally remote equiangular equiangular and similar equilateral triangle Examples exterior angle Fcap Find the locus GEOMETRY given angle given circle given line given point given straight line greater Hence intersect isosceles John's College late Fellow Let ABCD line drawn MATHEMATICAL measure meet middle point opposite sides parallel to CD parallelogram perpen perpendicular polygon produced quadrilateral figure radius rectangle right angles right-angled triangle Schools Second Edition segments Shew shortest line similar triangles student tangent THEOREM THEOREM VII Third Edition trapezium triangle ABC vertex