| Horatio Nelson Robinson - 1860 - 470 σελίδες
...EC to each; then BC = DE + EC. But DE + EC, is greater than DC. Therefore BC>DC. Hence the theorem ; if two triangles have two sides of one equal to two sides of the other, etc. THEOREM XXIII. A perpendicular is the shortest line that can be drawn from any point to... | |
| Horatio Nelson Robinson - 1868 - 276 σελίδες
...to each ; then BC = DE + E0. But DE + E0 is greater than DC. Therefore BC> DC. Hence the theorem ; if two triangles have two sides of one equal to two sides of the other, etc. Cot. Any point out of the perpendicular drawn from the middle point of a Hne, is unequally... | |
| William Frothingham Bradbury - 1872 - 124 σελίδες
...BFand DE trisect the diagonal A C. 50. If two triangles have two sides of the one equal respectively to two sides of the other, and the included angles supplementary, the triangles are equivalent. 51. The diagonals divide a parallelogram into four equivalent triangles. Two triangles standing on... | |
| William Frothingham Bradbury - 1872 - 262 σελίδες
...and DE trisect the diagonal A C. 50. If two triangles have two sides of the one equal respectively to two sides of the other, and the included angles supplementary, the triangles are equivalent. 51. The diagonals divide a parallelogram into four equivalent triangles. Two triangles standing on... | |
| Isaac Sharpless - 1879 - 282 σελίδες
...FH= GHDH common./ , (I. 2), £tf + HF > EF \BG'> EF. (Constr.), EG = BC/ Proposition 23. Theorem. — If two triangles have two sides of one equal to two sides of the other, each to each, but the third sides unequal, the angle contained by the two sides of the one which... | |
| William Frothingham Bradbury - 1880 - 260 σελίδες
...and ED trisect the diagonal A G. 104. If two triangles have two sides of the one equal respectively to two sides of the other, and the included angles supplementary, the triangles are equivalent. 105. The diagonals divide a parallelogram into four equivalent triangles. Two triangles standing on... | |
| Education Ministry of - 1880 - 238 σελίδες
...questions to be answered. _ 1. From a given point draw a straight line equal to a given straight line. 2. If two triangles have two sides of one equal to two sides of the other, each to each, and likewise their bases equal, the two triangles shall be equal in every respect.... | |
| Education Ministry of - 1882 - 292 σελίδες
...questions to be answered. 1. Prom a given point draw a straight line equal to a given straight line. 2. If two triangles have two sides of one equal to two sides of the other, each to each, and likewise their bases equal, the two triangles shall bo equal in every respect.... | |
| Isaac Sharpless - 1882 - 286 σελίδες
...Sclcolium. — This proposition shows that if we have two triangles of any shape, in which we can find two sides -of one equal to two sides of the other, and also the angles contained by these equal sides equal to each other, it is safe to conclude that the... | |
| Richard Anthony Proctor - 1887 - 202 σελίδες
...form a separate proposition — of which we shall presently have occasion to make use. PROP. II. — If two triangles have two sides of one equal to two sides of the other, each to each, and the angles opposite one pair of equal sides equal ; then, if G the angles... | |
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