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" Now (4)2+(3)2=25 sq. ft. ; and the square described on BC also contains 25 sq. ft. Hence, the square described on the hypothenuse of any right-angled triangle, is equal to the sum of the squares described on the other two sides. "
Higher Arithmetic, Or, the Science and Application of Numbers: Combining the ... - Σελίδα 373
των James Bates Thomson - 1862 - 422 σελίδες
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...BC^AB'-f-AC". Therefore, The square described on the hypolhcnuse of a right-angled triangle, is equivalent to the sum of the squares described on the other two sides. Cor. 1. Hence, by transposition, the square of one of the sides of a right-angled triangle is equivalent...

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...right-angled triangle equal to ? In every right-angled triangle, the square described on the hypothenuse, is equal to the sum of the squares described on the other two sides. Thus, if ABC be a rightangled triangle, right-angled at C, then will the square D, described on AB,...

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...principle in geometry, that the square described on the hypothenuse of a right-angled triangle, is equal to the sum of the squares described on the other two sides. (Leg. IV. 11. Euc. I. 47.) Thus if the base of the triangle ABC is 4 feet, and the perpendicular 3...

HIGHER ARITHMETIC; OR THE SCIENCE AND APPLICATION OF NUMBERS; COMBINING THE ...

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...perpendicular AC, contain as many square feet as the square described on the hypothenuse BC. Now (4)2+(3)2r=25 sq. ft. ; and the square described on BC also contains...any right-angled triangle^ is equal to the sum of the squares described on the other two sides. OBS. Since the square of the hypothenuse BC, is 25, it...




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