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" Multiply the integer of the quotient by the divisor, and to the product add the remainder, if any ; and the result will equal the dividend, if the work is right. "
A Treatise on Arithmetic ... - Σελίδα 77
των Noble Heath - 1855 - 455 σελίδες
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The New System of Practical Arithmetic: Whereby Most of the Various Problems ...

Charles Potts - 1835 - 202 σελίδες
...dividend. In this case- it is called short division, but otherwise long division. PROOF. — Multiply the quotient by the divisor, and to the product add the remainder. EXAMPLES. 1. Divide 963 by 3. Dividend. Divisor 3)963 Quotient 321 OPERATION. — As the divisor does...

The Mercantile Arithmetic: Adapted to the Commerece of the United States, in ...

Michael Walsh - 1838 - 346 σελίδες
...every figure so brought down, till the number be sufficient to contain the divisor. PROOF. Multiply the quotient by the divisor, and to the product add the remainder, and the sum will be equal to the dividend, if the .work be right. dividend, then divide the remaining...

Porter's New System of Mathematics: With the Addition of a Complete Ready ...

James H. Porter - 1841 - 210 σελίδες
...every figure so brought down, till the number be sufficient to contain the divisor. Proof. Multiply the quotient by the divisor, and to the product add the remainder, and the sum will be equal to the dividend, if the work is right. When there are ciphers annexed to...

A Treatise of Arithmetic: Designed for the Use of the Elementary Schools ...

1843 - 142 σελίδες
...other figures ; and to the last remainder annex the figures cut off from the dividend. PKOOF. Multiply the quotient by the divisor, and to the product add the remainder, if any ; the sum should be the dividend. Or cast the nines out of the divisor, dividend, quotient,...

Watson's Tutor's assistant; or, Complete school arithmetic

William Watson (of Beverley.) - 1845 - 188 σελίδες
...under it ; and for every nnit oner, carry ten to the next figure of the dividend. PROOF. — Multiply the quotient by the divisor, and to the product add the remainder, if any ; the product will be equal to the dividend if the work is right. EXAMPLES. (1) Divisor 3)743625798...

A New System of Arithmetic and Mathematics

James H. Porter - 1845 - 254 σελίδες
...every figure so brought down, till the number be sufficient to contain the divisor. Proof. Multiply the quotient by the divisor, and to the product add the remainder, and the sum will be equal to the dividend, if the work is right. When there are ciphers annexed to...

Elements of Arithmetic: Part I : Adapted to the Use of Common ..., Μέρος 1

Z. Jones - 1845 - 58 σελίδες
...Divide 576 by 4. Ans. 144. 2. Divide 4284 by 6. Ans. 714. To verify a process in division, multiply the quotient by the divisor, and to the product add the remainder, (if there be any,) and if the result agree with the dividend the work is right. 3. Divide 8961 by 124....

Arithmetic: In which the Principles of Operating by Numbers are Analytically ...

Daniel Adams - 1848 - 354 σελίδες
...equal to the dividend. NOTE 1. — To prove division, if there be a remainder. Multiply the integers of the quotient by the divisor, and to the product add the remainder. If the work be right, their eum will be equal to the dividend. Example. — Divide 1145 by 7. OPERATION....

Adam's New Arithmetic: Arithmetic, in which the Principles of Operating by ...

Daniel Adams - 1848 - 330 σελίδες
...equal to the dividend. NOTE 1 . — To prove division, if there be a remainder. Multiply the integers of the quotient by the divisor, and to the product add the remainder. If the work be right, their sum will be equal to the dividend. Example. — Divide 1145 by 7. OPERATION....

Arithmetic: In which the Principles of Operating by Numbers are Analytically ...

Daniel Adams - 1848 - 322 σελίδες
...equal to the dividend. ' NOTE 1. — To prove division, if there be a remainder. Multiply the integers of the quotient by the divisor, and to the product add the remainder. If the work be right, their sum will be equal to the dividend. Example. — Divide 1145 by 7. OPERATION....




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