TABLE of the Areas of the Segments of a Circle, the diameter of which is Unity, and supposed to be divided into 1000 equal Parts.

USE OF THE ABOVE TABLE.

To find the Area of a Segment of a Circle.

RULE. Divide the height or versed sine by the diameter of the circle, and find the quotient in the column of versed sines. Take the area noted in the next column, and multiply it by the square of the diameter, and it will give the area required.

EXAMPLE. Required the area of a segment; its height being 10, and the diame ter of the circle 50 feet.

10÷50.2, and .2, per table,=.11182; then .11182×50*279.55 Ans.

1.3209 .408 1.3972

.452

1.4775 .496

1.5628

.364 1.3225 .409 1.3990
.365 1.3241 .410 1.4008 .454 1.4813 .498
.366 1.3258 .411 1.4025 .455 1.4832 .499
.367 1.3274 .412 1.4043 .456 1.4851 .500
.368 1.3291

.453

1.4794

.497

1.5648

1.5668

1.5688

1.5708

To find the Length of an Arc of a Circle by the foregoing Table.

RULE. Divide the height by the base, find the quotient in the column of heights, and take the length of that height from the next right-hand column. Multiply the length thus obtained by the base of the arc, and the product will be the length of the arc required.

EXAMPLE.-What is the length of an arc of a circle, the span or base being 100 feet, and the height 25 feet?

25-100.25, and .25, per table, gives 1.1591; which, being multiplied by 100 - 115.9100, the length.