Mathematics: Compiled from the Best Authors, and Intended to be the Text-book of the Course of Private Lectures on These Sciences in the University at Cambridge, Τόμος 1W. Hilliard, 1808 |
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Σελίδα 118
... annum ? Ans . 7501 . 4. If a footman travel 130 miles in 3 days , when the days are 12 hours long ; in how many days , of 10 hours each , may he travel 360 miles ? Ans . days . 5. If 120 bushels of corn can serve 14 horses 56 days ; how ...
... annum ? Ans . 7501 . 4. If a footman travel 130 miles in 3 days , when the days are 12 hours long ; in how many days , of 10 hours each , may he travel 360 miles ? Ans . days . 5. If 120 bushels of corn can serve 14 horses 56 days ; how ...
Σελίδα 164
... annum , which premium per cent . per annum , or interest of 100l . for a year , is cailed the rate of interest . Interest is of two sorts , simple and compound . Simple interest is that , which is allowed only for the prin- cipal lent ...
... annum , which premium per cent . per annum , or interest of 100l . for a year , is cailed the rate of interest . Interest is of two sorts , simple and compound . Simple interest is that , which is allowed only for the prin- cipal lent ...
Σελίδα 165
... annum ? 4501 . 5 1,00 ) 22 ° 50 20 10 ̊00 Ans . 221. and = " 5 = 10s . 2. What is the interest of 7201. for 3 years , at 5 per cent . per annum ? 7201 . 5 36'00 36 3 1081. Ans . 3. What is the interest of 1071. for 117 days , at 4 per ...
... annum ? 4501 . 5 1,00 ) 22 ° 50 20 10 ̊00 Ans . 221. and = " 5 = 10s . 2. What is the interest of 7201. for 3 years , at 5 per cent . per annum ? 7201 . 5 36'00 36 3 1081. Ans . 3. What is the interest of 1071. for 117 days , at 4 per ...
Σελίδα 166
... annum ? Ans . $ 182 25 . 5. What is the interest of 2131. from Feb. 12 , to June 5 , 1796 , it being leap year , at 3 per cent . per annum ? Ans . 21. 6s . 6d . 31339 . SIMPLE INTEREST BY DECIMALS . RULE . * 501 Multiply continually the ...
... annum ? Ans . $ 182 25 . 5. What is the interest of 2131. from Feb. 12 , to June 5 , 1796 , it being leap year , at 3 per cent . per annum ? Ans . 21. 6s . 6d . 31339 . SIMPLE INTEREST BY DECIMALS . RULE . * 501 Multiply continually the ...
Σελίδα 167
... annum ? 945'5 * 05 47 ° 275 3 141'825 20 16 500 12 6'000 Ans . 1411. 16s . 6d . 2. What is the interest of 7961. 15s . for 5 years , at 41 per cent . per annum ? Ans . 1791. 5s . 4 d . 3. What is the interest of 5371. 15s . from ...
... annum ? 945'5 * 05 47 ° 275 3 141'825 20 16 500 12 6'000 Ans . 1411. 16s . 6d . 2. What is the interest of 7961. 15s . for 5 years , at 41 per cent . per annum ? Ans . 1791. 5s . 4 d . 3. What is the interest of 5371. 15s . from ...
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Συχνά εμφανιζόμενοι όροι και φράσεις
affirmative amount of 11 angle annuity annum arithmetical Bisect carats cent centre chord circle circumference coefficient common denominator completing the square compound interest compound quantity consequently cube root debt decimal denoted diameter difference Divide dividend division divisor draw equal equation EXAMPLES exponent figure fourth gallons geometrical progression geometrical series give given number greater greatest common measure half improper fraction infinite series less number logarithm manner Multiply negative NOTE nth root number of combinations number of terms number of things payment perpendicular polygon present worth PROBLEM proportion quadratic equation quotient radius ratio Reduce remainder repetend required to find right line RULE sides simple interest sine square root subtract Suppose surd taken tangent third unknown quantity vulgar fraction Whence whole number yards
Δημοφιλή αποσπάσματα
Σελίδα 175 - RULE.* — Multiply each payment by the time at which it is due; then divide the sum of the products by the sum of the payments, and the quotient will be the true time required.
Σελίδα 140 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Σελίδα 255 - Divide the first term of the dividend by the first term of the divisor, and write the result as the first term of the quotient. Multiply the whole divisor by the first term of the quotient, and subtract the product from the dividend.
Σελίδα 198 - A man was hired 50 days on these conditions. — that, for every day he worked, he should receive $ '75, and, for every day he was idle, he should forfeit $ '25 ; at the expiration of the time, he received $ 27'50 ; how many days did he work...
Σελίδα 149 - To the remainder bring down the first figure in the next period, and call it the dividend. 4. Involve the root to the next inferior power to that which is given, and multiply it by the number denoting the given power, for a divisor.
Σελίδα 315 - If A and B together can perform a piece of work in 8 days, A and C together in 9 days, and B and C in 10 days : how many days would it take each person to perform the same work alone ? Ans.
Σελίδα 124 - As the sum of the several products, Is to the whole gain or loss ; So is each man's particular product, To his particular share of the gain or loss.
Σελίδα 139 - ... and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek how often the divisor is contained...
Σελίδα 120 - When it is required to find how many of the first sort of coin, weight or measure, mentioned in the question, are equal to a given quantity of the last.
Σελίδα 132 - When one of the ingredients is limited to a certain quantity. RULE. Take the difference between each price and the mean rate, as before ; then,