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SIMLPE NUMBERS.

Time-book, showing hours worked for one week.*

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Total hours...

(ee) (ff)|(gg)|(hh)| (ii) | jj)| (kk) | (11)|(mm)

The above is from the ume-book of a small manufactory.

(a to j) Find the number of hours worked by each employe.

(k to t) Find the number of days (10 hours) worked by each employe.

(u to dd) Find the amount earned by each employe. (ee to jj) Find the number of hours of work done each day.

(kk) Find the sum of (a) to (j) inclusive; of (ee) to (jj) inclusive.

(11) Find the sum of (k) to (t) inclusive.

(mm) Find the sum of (u) to (dd) inclusive.

REVIEW.

1. Common multiples of 15 and 20 are

The least common multiple of 15 and 20 is

etc.

*Copy this time-book and write numbers in place of the letters; that is, instead of (a), write the number of hours worked by John Miller; in place of (k), write the number of days worked by John Miller, etc. Call 8 hours a day's work.

COMMON FRACTIONS.

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1. Add 1,, and . The 1. c. m. of 8, 10, and 5 is (a) Find the sum of 896, 5071%, and 344.

2. From 91 subtract 3.2. 1

= 40

.2 = 40°

(b) Find the difference of 17548 and 592.7.

3. Multiply 27 by 5. This means

(c) Find the product of 757-8 multiplied by 5.

4. Multiply 14 by . This means

1.

(d) Find the product of 536 multiplied by . Story.

5. Multiply 21 by . This means

(e) Find the product of 681 multiplied by .

6. Multiply 21 by 23. This means

(f) Find the product of 681 multiplied by 83.

7. Multiply 11 by 24. This means
(g) Find the product of 273 multiplied by 44.
8. Divide 7 by . (Change 7 to ths.)

(h) Find the quotient of 97 divided by . Story.
9. Divide by (Change to ths.)

3

(i) Find the quotient of 73 divided by Story.

10. Divide 73 by 2. (Change toths.)

(j) Find the quotient of 863 divided by 3.

11. Divide 28 (7) by 3. This means
(k) Find the quotient of 85 divided by 9.
12. Divide 213 by 5. This means

(1) Find the quotient of 6213 divided by 5.

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(1) Tell the meaning of each of the following, (2) solve, and (3)

tell a suggested number story.

This means

(1) $35.056 ÷ 8 =

Story.

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(s) At $.25 a dozen, how many lemons can I buy for $36.75?

(t) I paid $36.75 for 25 barrels of apples. How much did the apples cost per barrel?

(u) If one acre of land is worth $36.75, how much are 5.6 acres worth?

(v) If 2 chairs cost $37.24, how much will 9 chairs cost at the same rate?

*Pupils will most readily give a number story in such work as this, by letting the figures represent units of money, thus: At $.05 each, for $375.6 I could buy 7512 tablets. When the pupils are well grounded in this work, they may be encouraged to seek variety in their number stories.

DENOMINATE NUMBERS.

1. Twelve dozen are one gross.

2. At 48¢ a gross, 1 dozen buttons cost

cents.

3. At 5¢ a dozen, 1 gross of buttons cost

cents.

4. At 50¢ a gross, 6 dozen buttons cost

cents.

5. At 36¢ a gross, 3 dozen buttons cost

cents.

6. George bought pens at 50¢ a gross and sold them at the rate of 2 for 1 cent; on 1 gross he gained

(a) Henry bought pens at 604 a gross and sold them at the rate of 3 pens for 2 cents. How much did he gain on one gross? (b) How much on 7 gross ?

REVIEW.

(c) Make a receipted bill of the following goods sold by yourself to Mr. Frank H. Armstrong:

Aug. 2, 15 lb. shingle nails @ 4¢; Aug. 10, 6 lb. fence staples @ 54; Aug. 20, 130 lb. No. 9 fence. wire @24; Aug. 25, 1 keg 20d. nails @ $3.25.*

7. One fourth of a ream of paper is

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sheets.

pounds.

dollars.

10. When coal is $6 per ton, 7000 lb. cost

(d) Load of bran; gross weight, 2850 lb.; tare, 1050 lb. Find the value at $7.50 a ton.

(e) Multiply 36 square feet by 24, and divide the product thus obtained by 9 square feet. Story.

(f) Multiply 12 cubic feet by 15, and the product thus obtained by 6. Divide the last product by 27 cubic feet. Story.

* Ask the pupil to bring to school a shingle nail, a fence staple, a piece of No. 9 wire, and a 10d. nail; also to learn the current price of the articles named.

MEASUREMENTS.

1. Draw carefully upon your slate or paper, on a scale of inch to the rod, a diagram of a rectangular piece of land that is 30 rods by 40 rods.

(a) Find the perimeter of the land represented by the diagram you have drawn.

(b) Find its area in square rods.

(c) Find its area in acres.

(d) How much is the land worth at $72.50 an acre? (e) How much will it cost to build a fence around it at 45¢ a rod?

(f) A strip 4 rods wide across one side of the field contains how many square rods?

(g) A strip 8 rods wide across one side of the field contains how many acres?

2. Land 5 rods by 40 rods contains

3. Land 7 rods by 40 rods contains

4. Land 9 rods by 40 rods contains

Find the number of acres in each of the following:

(h) 32 rods by 5 rods.

(j) 32 rods by 22 rods.

(i) 32 rods by 26 rods. (k) 32 rods by 34 rods. each of the following:

Find the number of cords in
(1) 12 ft. by 8 ft. by 4 ft.
(n) 20 ft. by 4 ft. by 4 ft.
Find the number of square yards
(p) 30 feet by 40 feet.
(r) 18 feet by 21 feet.

Find the number of cubic yards
(t) 12 ft. by 6 ft. by 9 ft.
(v) 15 ft. by 9 ft. by 12 ft.

(m) 16 ft. by 6 ft. by 4 ft. (0) 21 ft. by 8 ft. by 4 ft. in each of the following: (q) 25 feet by 33 feet. (s) 35 feet by 40 feet. in each of the following: (u) 15 ft. by 12 ft. by 6 ft. (w) 21 ft. by 6 ft. by 18 ft.

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