An Elementary Treatise on Algebra, in Theory and Practice: With Attempts to Simplify ... that Science ... With Notes and Illustrations ... To which is Added an Appendix, on the Application of Algebra to GeometryHilliard, Gray, & Company, 1840 - 605 σελίδες |
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Σελίδα 4
... fourth , & c . , degree , is one in which the highest power of the unknown quantity is the third , fourth , & c . , powers ; and in general , an equation , in which the unknown quantity is called an equation of the mth degree , and each ...
... fourth , & c . , degree , is one in which the highest power of the unknown quantity is the third , fourth , & c . , powers ; and in general , an equation , in which the unknown quantity is called an equation of the mth degree , and each ...
Σελίδα 50
... fourth power of x is x1 ; the fourth power of x + y is ( x + y ) . If the quantity proposed be a compound one , the in- volution may either be represented by the proper index , or it may actually take place . If the quantity to be ...
... fourth power of x is x1 ; the fourth power of x + y is ( x + y ) . If the quantity proposed be a compound one , the in- volution may either be represented by the proper index , or it may actually take place . If the quantity to be ...
Σελίδα 52
... fourth root of 81a1b , or 256ax . 3abb , or 4ax2 . 8. Find the fifth root of -32a566 , or √2a2b * = √ ( a2b1 × 2 ) = ab2√2 , or No- 32a5210 243 8a2b2 4a2b2 2 3c3 c2 X 3c ) 2ab 2 4a1 C -No 3C ' or No4a2x No4√ a2√2o = 2ax3 , or No 9x ...
... fourth root of 81a1b , or 256ax . 3abb , or 4ax2 . 8. Find the fifth root of -32a566 , or √2a2b * = √ ( a2b1 × 2 ) = ab2√2 , or No- 32a5210 243 8a2b2 4a2b2 2 3c3 c2 X 3c ) 2ab 2 4a1 C -No 3C ' or No4a2x No4√ a2√2o = 2ax3 , or No 9x ...
Σελίδα 57
... fourth term of the root , & c . & c . 1. Extract the cube root of x2 - 6x + 15x1 — 20x3 + 15x2 - 6x + 1 . x - 6x + 15x - 20x + 15x2 - 6x + 1 ( x2 - 2x + 1 . ၄၆ 3x - 6x + 4x - 6x + 15x - 20x3 -6x3 + 12x1— 8x3 3x - 12x + 15x - 6x + 1 ...
... fourth term of the root , & c . & c . 1. Extract the cube root of x2 - 6x + 15x1 — 20x3 + 15x2 - 6x + 1 . x - 6x + 15x - 20x + 15x2 - 6x + 1 ( x2 - 2x + 1 . ၄၆ 3x - 6x + 4x - 6x + 15x - 20x3 -6x3 + 12x1— 8x3 3x - 12x + 15x - 6x + 1 ...
Σελίδα 65
... fourth . Their wages amounted to 32 shillings . What did each receive ? Let the sum received by the fourth , ..x + 4 = x + 7 = and x + 9 = third , second , first . ·· x + x + 4 + x + 7 + x + 9 = 32 , and , by transposition , 4x - 12 ...
... fourth . Their wages amounted to 32 shillings . What did each receive ? Let the sum received by the fourth , ..x + 4 = x + 7 = and x + 9 = third , second , first . ·· x + x + 4 + x + 7 + x + 9 = 32 , and , by transposition , 4x - 12 ...
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An Elementary Treatise on Algebra, in Theory and Practice: With Attempts to ... John D. Williams Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2018 |
An Elementary Treatise on Algebra, in Theory and Practice: With Attempts to ... John D. Williams Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2015 |
An Elementary Treatise on Algebra, in Theory and Practice: With Attempts to ... John D Williams Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2015 |
Συχνά εμφανιζόμενοι όροι και φράσεις
Algebra amount angle annuity answer arithmetical progression arithmetical series Assume bushels cent coefficients compound interest consequently continued fraction converging fractions cube cubic equation denominator denote the numbers difference divided divisor dollars expression factors Find the sum find the value formula four roots geometrical progression gives greater Hence infinite infinite series infinitum integral least value less logarithms miles multiplied number of days number of solutions number of terms proposed equation quadratic equation question quotient ratio reduced remainder Required the number Required the sum required to find rule scale of relation shillings side square numbers square root substituted subtracted Suppose surd taken at pleasure third three numbers tion transposition triangle unknown quantity value of x whence whole numbers yards
Δημοφιλή αποσπάσματα
Σελίδα 126 - In one of the given equations obtain the value of one of the unknown quantities in terms of the other unknown quantity; Substitute this value in the other equation and solve.
Σελίδα 544 - Two travellers, A and B, set out to meet each other, A leaving the town C at the same time that B left D.
Σελίδα 94 - A person has two horses, and a saddle worth £50 ; now, if the saddle be put on the back of the first horse, it will make his value double that of the second ; but if it be put on the back of the second, it will make his value triple that of the first ; what is the value of each horse ? Ans.
Σελίδα 258 - Then, as the difference of these results is to the difference of the two assumed numbers, so is the difference between the true result, and either of the former, to the correction of the number belonging to the result used ; which correction being added to that number when it is too little, or subtracted from it when it is too great, will give the root required, nearly.
Σελίδα 492 - There is a rectangular field, whose length is to its breadth in the proportion of 6 to 5. A part of this, equal to -£ of the whole, being planted, there remain for ploughing 625 square yards. What are the dimensions of the field ? 1 3.
Σελίδα 97 - If A and B together can perform a piece of work in 8 days, A and C together in 9 days, and B and C in 10 days : how many days would it take each person to perform the same work alone ? Ans.
Σελίδα 435 - At the 50th mile stone from London, A overtook a drove of geese which were proceeding at the rate of three miles in two hours ; and two hours afterwards met a stage waggon, which was moving at the rate of 9 miles in 4 hours.
Σελίδα 439 - There are four numbers in geometrical progression, the second of which is less than the fourth by 24 ; and the sum of the extremes is to the sum of the means, as 7 to 3. What are the numbers ? Ans.
Σελίδα 497 - Is. ; for each of which I paid as many shillings per yard as there were yards in its side. Now had each of them cost as many shillings per yard as there were yards in a side of the other, I should have paid 17s.
Σελίδα 96 - Divide the number 90 into 4 such parts, that the . first increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by 2, shall all be equal.