shown in Fig. 151, we may divide it into six triangles 2 in. on a side. The area of each c triangles equals the product of the base of the half its altitude. If the triangle is 2 in. on eɛ

.866n

2'

FIG. 151.

FIG. 152.

height ab of the triangle equals (2)2 (1) 1.732 in. The area of the triangle then equ

The area of the hexagon then equals 6 10.392 or 10.4 sq. in.

If we take a hexagon "n" in. on a side, as the area equals 6 X area of one triangle or 6 ×

(.866n is the height of each triangle) or 2.60

The area of a hexagon therefore equals squero of one side

24"

FIG. 155.

In the hexagon shown in Fig. 156, 1 in. on as the equilateral triangles has a true height or

.866'

998

.866 in. 1.73 in. or 2 in.

FIG. 156.

The distance ab across flats equals
Also the distance cd across corners e
Therefore the ratio of the distance ac

-1.73"