Arithmetic: In which the Principles of Operating by Numbers are Analytically Explained and Synthetically Applied : Illustrated by Copious Examples : Designed for the Use of Schools and AcademiesJ.H. Spalter & Company, 1848 - 312 σελίδες |
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Αποτελέσματα 1 - 5 από τα 100.
Σελίδα 18
... SOLUTION . - One of these numbers contains 4 tens and 3 units . The other number contains 2 tens and 5 units . To unite these two numbers together into one , write them down one un- der the other , placing the units of one number ...
... SOLUTION . - One of these numbers contains 4 tens and 3 units . The other number contains 2 tens and 5 units . To unite these two numbers together into one , write them down one un- der the other , placing the units of one number ...
Σελίδα 20
... SOLUTION . -Writing the numbers as already described , we add the units , and find them to be 15 , equal to 5 units , which we write in units ' place , adding the 1 ten with the tens ; which being added together are 15 tens , equal to 5 ...
... SOLUTION . -Writing the numbers as already described , we add the units , and find them to be 15 , equal to 5 units , which we write in units ' place , adding the 1 ten with the tens ; which being added together are 15 tens , equal to 5 ...
Σελίδα 25
... SOLUTION . -We begin with the units , saying , 4 ( units ) from 7 , ( units , ) and there remain 3 , ( units , ) which we set down directly under the column in units ' place . Then proceeding to the next column , we say , 1 ( ten ) from ...
... SOLUTION . -We begin with the units , saying , 4 ( units ) from 7 , ( units , ) and there remain 3 , ( units , ) which we set down directly under the column in units ' place . Then proceeding to the next column , we say , 1 ( ten ) from ...
Σελίδα 26
... SOLUTION . The same difficulty presents itself here as in the last example , that is , the unit figure in the subtrahend is greater than the unit figure in the minu- end . To obviate this difficulty , we may take 1 ( ten ) from the 8 ...
... SOLUTION . The same difficulty presents itself here as in the last example , that is , the unit figure in the subtrahend is greater than the unit figure in the minu- end . To obviate this difficulty , we may take 1 ( ten ) from the 8 ...
Σελίδα 27
... SOLUTION.In this example we have 0 units from which to subtract 9 units , and going to tens of the minuend , we have 0 tens , nor hundreds , nor thousands ; but we have 1 ten thousand from which , borrowing 10 units , we have 9990 ...
... SOLUTION.In this example we have 0 units from which to subtract 9 units , and going to tens of the minuend , we have 0 tens , nor hundreds , nor thousands ; but we have 1 ten thousand from which , borrowing 10 units , we have 9990 ...
Άλλες εκδόσεις - Προβολή όλων
Συχνά εμφανιζόμενοι όροι και φράσεις
acres amount annexing apples Arithmetic bought bushels called ciphers common divisor common fraction composite number compound interest Compound Numbers contained cord cost cube root cubic decimal fractions diameter divided dividend division dollars equal EXAMPLES FOR PRACTICE expressed factors farthings feet long figure foot frac gallons Give given number greatest common divisor Hence hogshead hundred hundredths improper fraction inches integers last term length measure merchant miles mills minuend mixed number months multiplicand multiply NOTE number of terms OPERATION oranges paid payment pence pieces pound principal proper fraction proportion pupil quantity quarts Questions quotient rate per cent ratio receive Reduce remainder rule shillings side sold solid feet SOLUTION square miles square root subtraction subtrahend tens tenths third thousandths tion Troy weight units weight whole number write
Δημοφιλή αποσπάσματα
Σελίδα 236 - Reduce compound fractions to simple ones, and mixt numbers to improper fractions ; then multiply the numerators together for a new numerator, and the denominators for. a new denominator.
Σελίδα 146 - Thirty days hath September, April, June, and November ; All the rest have thirty-one, Except the second month alone, Which has but twenty-eight, in fine, Till leap year gives it twenty-nine.
Σελίδα 49 - The number to be divided is called the dividend. The number by which we divide is called the divisor. The number which shows how many times the divisor is contained in the dividend is called the quotient.
Σελίδα 145 - Time. 60 seconds (S.) make 1 minute, marked M. 60 minutes, 1 hour, h. 24 hours, 1 day, d. 7 days, 1 week, ' w. 4 weeks, 1 month, mo. 13 months, 1 day and 6 hours, 1 Julian year, yr. Thirty days hath September, April, June, and November, February twenty-eight alone, all the rest have thirty-one.
Σελίδα 243 - If 248 men, in 5 days, of 11 hours each, can dig a trench 230 yards long, 3 wide...
Σελίδα 196 - What is the interest of $216'80, at 7 per cent., for 1 month ? for 2 months ? 3 mo. ? 4 mo. ? 5 mo. ? 6 mo. ? 7 mo. ? 8 mo. ? 9 mo.? 10 mo. ? 11 mo.
Σελίδα 279 - RULE.* — Multiply the sum of the extremes by the number of terms, and half the product will be the answer.
Σελίδα 143 - TABLE. 4 gills (gi.) - make - - 1 pint, marked pt. 2 pints ------- 1 quart, - - - qt. 4 quarts ------ 1 gallon, - - - gal. 31£ gallons ------ 1 barrel, - - - bar.
Σελίδα 278 - The extremes and the number of terms being given, to find the sum of all the terms.
Σελίδα 41 - When the multiplier is 10, 100, 1000, or 1 with any number of ciphers annexed, annex as many ciphers to the multiplicand as there are ciphers in the multiplier, and the multiplicand, so increased, will be the product required.