 | Etienne Bézout - 1824 - 238 σελίδες
...second by the third and dividing their product by the first. For it is plain (174) the fourth term may be found by dividing the product of the extremes by the first term. But this product is the same as the prod net of the means. Then the fourth term may also... | |
 | George Peacock - 1830 - 732 σελίδες
...proportion may be found by dividing the product of the means by the other extreme ; and either of the means may be found by dividing the product of the extremes by the other mean. 387- In order to arrange the quantities in the question, mcnt ^"thc in the proportion which... | |
 | Stephen Chase - 1849 - 348 σελίδες
...of the means by the given extreme. Or, if the extremes and one mean be given, the other mean will bo found by dividing the product of the extremes by the given mean. Thug, If x: 6 = 11 : 22, then 22x=6C; and x — 3. So, if 5 : x = 10 : 40, then 10a = 200 ; and a;... | |
 | Benjamin Greenleaf - 1851 - 332 σελίδες
...two extremes of the proportion, 14 and 9, and the two means, IS and 7, thus 14 X 9= 18 X 7ART. 245. If the extremes and one of the means are given the other mean may le found' by dividing the prodrtct of the extremes by the given mean. Thus, if the extremes are 3 and... | |
 | Benjamin Greenleaf - 1854 - 342 σελίδες
...extremes of the proportion, 14 and 9, and the two means, 18 and 7, thus 14 X 9 = 18 X 7. ART. 24*5. If the extremes and one of the means are given the...be found, by dividing the product of the extremes ly the, given mean. Thus, if the extremes are 3 and 24, and the given mean 6, the other mean is 12... | |
 | Benjamin Greenleaf - 1857 - 336 σελίδες
...them? — Art. 241. 3 luw does the product of the extremes compare with that of the means ? ART. 242. If the extremes and one of the means are given, the...6, the other mean is 12 ; because 24 X 3 = 72; and 72 -r- 6 = 12. AKT. 243. If the means and one of the extremes are given, the other extreme may be found... | |
 | Benjamin Greenleaf - 1857 - 452 σελίδες
...extremes of the proportion, 16 and 10, and the two means, 8 and 20 ; thus, 16 X 10 = 8 X 20. Hence, 1. If the extremes and one of the means are given, the...dividing the product of the extremes by the given mean ; or, 2. If the means and one of the extremes are given, the other extreme may be found by dividing... | |
 | Benjamin Greenleaf - 1858 - 456 σελίδες
...extremes of the proportion, 1C and 10, and the two means, 8 and 20 ; thus, 16 X 10 = 8 X 20. Hence, 1. If the extremes and one of the means are given, the...dividing the product of the extremes by the given mean ; or, 2. If the means and one of the extremes are given, the other extreme may be found by dividing... | |
 | Benjamin Greenleaf - 1858 - 458 σελίδες
...extremes of the proportion, 16 and 10, and the two means, 8 and 20; thus, 16 X 10 — 8 X 20. Hence, 1. If the extremes and one of the means are given, the...dividing the product of the extremes by the given mean ; or, 2. If the means and one of the extremes are given, the other extreme may be found by dividing... | |
 | Benjamin Greenleaf - 1858 - 472 σελίδες
...means, 8 and 20 ; thus, 16 X 10 = 8 X 20. Hence, 1. If the extremes and one of the means are given, ike other mean may be found by dividing the product of the extremes by the given mean ; or, 2. If the means and one of the extremes are given, the other extreme may be found by dividing... | |
| |
If the extremes and one of the means are given the other mean may be found by dividing the product of the extremes by the given mean. 
