From the second, 2; hence y=4. 22. Find the values of x and y in the Equations Dividing the first Equation by the second, Reducing each member of this Equation to its lowest terms, from which x will be found 2, or ; and we shall now easily find y=3, or -24. 23. Find the values of x and y in the Equations x3+xy239, and x2y+y3-26. Substituting this value of y in the first Equation, 24. Find the values of x and y in the Equations x-y=4, and x3-y33-16. Dividing each side of the second Equation by the corresponding side of the first, The value of x will now be found to be 7, or -3. 25. Find the values of x and y in the Equations x2-y2-5, and xa—ya—65. Dividing the second Equation by the first, x2+y21-3. Adding this Equation to the first, 2x218; then x=±3. Substituting this value of x in the first Equation, we shall find y =±2. 26. Find the values of x and y in the Equations x+y=60, and 2(x2+y2)=5xy. Substituting this value of x for x in the first Equation, from which y will be found equal to 40, or 20; and x is now easily found equal to 20, or 40. 27. Find the values of x and У in the Equations Substituting for xy in this Equation, its value from the first Equation, Substituting this value of 23 in the fourth Equation, 28. Find the values of x and y in the Equations xy=25, and 23+y3=10xy. Substituting the values of xy and x3 in the second Equation, Clearing this Equation of fractions, 15625+y=250y3; from which y3 will be found = 125; hence y=5. Substituting 5 for y in the first Equation, we find x=-5. 29. Find the values of x and y in the Equations x2'—y2—(x+y)=8, and (x−y)2(x+y)=32. Equating this value of (x-y)2, with its value in the fourth Equation, Developing, and clearing this Equation of fractions, by multiplying it by (x+y)2, we shall find 64+16(x+y)+(x+y)2=32(x+y). Transposing, and uniting similar terms, (x+y)2-16(x+y)=-64. This Equation will give x+y=8; then x=8—y. 64-16y-88; hence y=3. Then since x=8-y, we have x= —8—3—5. 30. Find the values of x and y in the Equations, x+√xy+y=7, and x2+xy+y2=21. Dividing the second Equation by the first, x−√xy+y=3. Substituting this value of x in the fifth Equation, 31. Find the values of x and y in the Equations Equating the two values of√xy from the second and third Equations, Clearing this Equation of fractions, and reducing, 20xy=5(x+y)2—64(x+y). Dividing this Equation by 5, and subtracting the result from the fifth Equation, |