 | Edward Olney - 1872 - 562 σελίδες
...parallelogram is equivalent to a rectangle of the same base and altitude (313). 323. COB. 3. — The area of a triangle is equal to one-half the product of its base and altitude; fora triangle is one-half of a parallelogram of the same base and altitude (3 14). 324. COB. 4. —... | |
 | Edward Olney - 1872 - 472 σελίδες
...parallelogram is equivalent to a rectangle of the same base and altitude (313). 323. COR. 3. — The area of a triangle is equal to one.half the product of its base and altitude ; for a triangle is one.half of a parallelogram of the same base and altitude (3 14). 32Ф. COR. 4.... | |
 | Joseph Ficklin - 1881 - 406 σελίδες
...altitude 6 ft. 9 x fi SOLUTION. — — = 27 ; hence, the area is 27 sq. ft. a EXPLANATION. — The area of a triangle is equal to one-half the product of its base and altitude. FORMULA : Area of triangle = \ (Base x Altitude). 2. What is the area of a triangle whose base is 50... | |
 | Edward Olney - 1883 - 352 σελίδες
...parallelogram is equivalent to a rectangle of the same base and altitude (332). 347. COROLLARY 3.—The area of a tri-angle is equal to one-half the product of its base and altitude; for a triangle is one-half of a parallelogram of the same base and altitude (333). 348. COROLLARY 4.—Parallelograms... | |
 | Alfred Hix Welsh - 1883 - 326 σελίδες
...stones, of rectangular form, 2 ft. 3 in. by 10 in., will be required to pave it? THEOREM VI. • The area of a triangle is equal to one-half the product of its base by its altitude. r- Let ABD be any triangle; then 7 will ABD = $ a b. ^/ For, draw DC parallel to AB,... | |
 | Webster Wells - 1886 - 392 σελίδες
...and their bases equal to b and 6' respectively. Then, area ABCD = area ABD + area BCD. But since the area of a triangle is equal to one-half the product of its base by its altitude (§ 327), area ABD = \ ax 6, and urea. BCD = la xb'. Therefore, area ABCD =Jax6+Jax6'... | |
 | George Albert Wentworth - 1887 - 264 σελίδες
...are the points (2, 1), (3, - 2), (- 4, - 1). A ns. 10. It is shown in Elementary Geometry that the area of a triangle is equal to one-half the product of its base and its altitude ; hence this problem may be solved by performing the following operations : (i.) Find... | |
 | William Chauvenet - 1887 - 342 σελίδες
...AD and DC respectively, the rectangle OD will be equivalent to one-half the rectangle ABCD. 6. The area of a triangle is equal to one-half the product of its perimeter by the radius of the inscribed circle. 7. The area of a rhombus is one-half the product of... | |
 | William Chauvenet, William Elwood Byerly - 1887 - 331 σελίδες
...AD and DC respectively, the rectangle OD will be equivalent to one-half the rectangle ABCD. 6. The area of a triangle is equal to one-half the product of its perimeter by the radius of the inscribed circle. 8. The straight line joining the middle points of... | |
 | New Jersey. State Board of Education - 1888 - 694 σελίδες
...3. Prove that the sum of the angles of any triangle is equal to two right angles. 4. Prove that the area of a triangle is equal to one-half the product of its base and altitude. 5. Prove that the side of a regular inscribed hexagon is equal to the radius of the circle. rods up... | |
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The area of a triangle is equal to one-half the product of its base and altitude. 
