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PROPOSITION XXIV. THEOREM

362 If two polygons are composed of the same number of triangles, similar each to each, and similarly placed, the polygons are similar.

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HYPOTHESIS. The ABC, ACD, and ADE are similar respectively to the ▲ A'B'C', A'C'D', and A'D'E', and similarly placed.

CONCLUSION. The polygons ABCDE and A'B'C'D'E' are similar.

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In like manner it may be shown that the other corresponding

angles of the polygons are equal.

That is, the polygons are mutually equiangular.

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That is, the homologous sides of the polygons are proportional.

.. the polygons are similar.

"Similar polygons are polygons which have their homologous angles equal and their homologous sides proportional."

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Q. E. D.

PROPOSITION XXV. THEOREM

363 If two polygons are similar, they are composed of the same number of triangles, similar each to each, and similarly placed.

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HYPOTHESIS. The polygons ABCDE and A'B'C'D'E' are similar. CONCLUSION. The AABC, ACD, and ADE are similar respectively to the A A'B'C', A'C'D', and A'D'E'.

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Subtracting,

and BCA = ▲ B'C'A'.

ACD=ZA'C'D'.

Again, BC: B'C' = AC : A'C',

and BC: B'C' = CD : C'D'.

.. AC : A'C' = CD : C'D'.

.. the ▲ ACD and A'C'D' are similar.

Likewise the A ADE and A'D'E' are similar.

Q. E. D.

364 COROLLARY. Two similar polygons are equal, if any

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Ax. 4

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Ax. 11

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two homologous lines are equal.

PROPOSITION XXVI. THEOREM

365 If in a right triangle an altitude is drawn to the hypotenuse:

1 The two triangles thus formed are similar to the whole triangle and to each other.

2 The altitude is the mean proportional between the segments of the hypotenuse.

3 Each leg of the right triangle is the mean proportional between the hypotenuse and the adjacent segment.

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HYPOTHESIS. In the rt. ▲ BAC, AD is to BC, the hypotenuse.
CONCLUSION. 1 The ▲ BDA, ADC, and BAC are similar.

PROOF

The rt. A BDA and BAC have the Z B common;

... they are similar.

The rt. A ADC and BAC have the C common;

.. they are similar.

The ABDA and ADC are similar,

for each is similar to the ▲ BAC.

§ 353

§ 353

Proved

2 AD is the mean proportional between BD and DC.

PROOF

In the similar ▲ BDA and ADC,

BD: AD = AD : DC.

§ 349

3 BA is the mean proportional between BC and BD, and CA is the mean proportional between CB and CD.

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366 COROLLARY 1.

The squares of the legs of a right triangle are proportional to the adjacent segments of the hypote

nuse.

PROOF

From the proportions in the third part of the theorem,
BA2 = BC × BD, and CA2 = CB × CD.

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§ 328

Q. E. D.

367 COROLLARY 2. The altitude upon the hypotenuse of a right triangle is equal to the product of the legs divided by the hypotenuse.

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368 COROLLARY 3. The perpendicular drawn from any point

in the circumference of a circle to the diameter is the mean proportional between the segments of the diameter.

PROPOSITION XXVII. THEOREM

369 The square of the hypotenuse of a right triangle is equal to the sum of the squares of the two legs.

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HYPOTHESIS. BC is the hypotenuse of the rt. ▲ BAC.
CONCLUSION. BC2 = AB2+AC2.

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370 COROLLARY 1. The square of either leg of a right triangle is equal to the difference of the squares of the hypotenuse and the other leg.

371 COROLLARY 2. The side and the diagonal of

a square are incommensurable.

d2 = s2 + s2 = 2s2. . d = s√2.

B

372 DEFINITION. The projection of a line AB upon a line MN is that part of MN included between the feet of the perpendiculars drawn from A and B to MN. Thus, CD is the projection of AB upon MN.

M

-N

C

D

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