A Key to the Elementary Treatise on AlgebraChase and Nichols, 1863 - 56 σελίδες |
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Σελίδα 3
... 1. Performed . 2. Horse $ 100 . SECTION I. Saddle $ 10 . 3. 6 bushels of each . 4. 11 of each . 5. 5 melons ; 10 pears ... 1st 8 , 2d 16 , 3d 24 guineas . 11. Wife $ 36000 ; elder son $ 27000 ; younger son $ 18000 . 12. 120 cavalry ; 360 ...
... 1. Performed . 2. Horse $ 100 . SECTION I. Saddle $ 10 . 3. 6 bushels of each . 4. 11 of each . 5. 5 melons ; 10 pears ... 1st 8 , 2d 16 , 3d 24 guineas . 11. Wife $ 36000 ; elder son $ 27000 ; younger son $ 18000 . 12. 120 cavalry ; 360 ...
Σελίδα 4
... 1. Performed . 2. 1st $ 23000 ; 2d $ 33000 . 3. 734 and 156 miles . 4. A's 15 , B's 35 , C's 50 years . 5. 1st 8 lbs ; 2d 22 lbs ; 3d 30 lbs ; 4th 60 lbs . 6. 6 , 8 , 10 , 12 , and 14 years respectively . 7. Black $ 30 ; green $ 32 ...
... 1. Performed . 2. 1st $ 23000 ; 2d $ 33000 . 3. 734 and 156 miles . 4. A's 15 , B's 35 , C's 50 years . 5. 1st 8 lbs ; 2d 22 lbs ; 3d 30 lbs ; 4th 60 lbs . 6. 6 , 8 , 10 , 12 , and 14 years respectively . 7. Black $ 30 ; green $ 32 ...
Σελίδα 5
Thomas Sherwin. ART . 11 . 1. Performed . SECTION 111 . 2. Finer $ 6 ; coarser $ 4 per yard . 3. A's 50 ; B's 40 years . 4. 20 each . 5. Sum distributed 153d . Eldest 60d .; 2d 42d .; 3d 30d .; 4th 21d . 6. 1st 10s .; 2d 7s .; 3d 8s ...
Thomas Sherwin. ART . 11 . 1. Performed . SECTION 111 . 2. Finer $ 6 ; coarser $ 4 per yard . 3. A's 50 ; B's 40 years . 4. 20 each . 5. Sum distributed 153d . Eldest 60d .; 2d 42d .; 3d 30d .; 4th 21d . 6. 1st 10s .; 2d 7s .; 3d 8s ...
Σελίδα 6
... 1st 30 cents ; 2d and 3d 15 cents each . 15. Whole number 30. The 1st had 10 ; 2d 6 ; 3d 4 ; 4th 10 16. 1st horse $ 100 ; 2d horse $ 150 ; chaise $ 300 . 17. Income $ 1200 ; he spends $ 650 . 18. 45 sheep . 19. 1st £ 56 ; 2d £ 35 ; 3d ...
... 1st 30 cents ; 2d and 3d 15 cents each . 15. Whole number 30. The 1st had 10 ; 2d 6 ; 3d 4 ; 4th 10 16. 1st horse $ 100 ; 2d horse $ 150 ; chaise $ 300 . 17. Income $ 1200 ; he spends $ 650 . 18. 45 sheep . 19. 1st £ 56 ; 2d £ 35 ; 3d ...
Σελίδα 7
... 1st car 18 miles ; 2d car 20 miles per hour . 23. $ 150 . 24. $ 110 . 25. 139 . SECTION VI . ART . 15 . 1. Horse $ 150 ; chaise $ 250 . 2. 80 gallons . 3. Greater 35 ; less 25 . 4. Performed . 5. 20 tons . 6. $ 72 . 7. Greater 75 ; less ...
... 1st car 18 miles ; 2d car 20 miles per hour . 23. $ 150 . 24. $ 110 . 25. 139 . SECTION VI . ART . 15 . 1. Horse $ 150 ; chaise $ 250 . 2. 80 gallons . 3. Greater 35 ; less 25 . 4. Performed . 5. 20 tons . 6. $ 72 . 7. Greater 75 ; less ...
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1+m+n 14th performed 1st and 2d 24 a b² 2d and 3d 2d performed 5th inclusive 80 miles 9 x² a¹ b² a² b² c² a² c² a² cm a² x a²bc a³ 3 a² a³ d² a4 m² ac² b² c³ b² c4 breadth bushel c² d² c3 d³ cents chaise Changing the sign cows equation gives gallons galls h³ n³ Hence Horse learner verify m² n m² x y m² x² m²-n² m²+1 m³ x³ miles per hour np-mq number killed original equations preceding formulæ Progression represent the number sheep son's subtracting and canceling Wheat x y² x y³ x² y x² y² x² y³ x³ y x5 y³ x6 y³ x⁹ y¹º y⁹ yards
Δημοφιλή αποσπάσματα
Σελίδα 3 - cavalry; 360 artillerymen; 720 infantry. 13. A 8 days, 72 rods; В 16 days, 112 rods; С 80 days, 400 rods. 14. 8 yds, 16 yds, and 24 yds respectively. 15. Sheep $2 ; calf $4 ; cow $20. 16. Greater 14 galls ; less 7 galls. 17. Beef 10 Ibs; mutton 20 Ibs. 18. 32 of each. 19.
Σελίδα 26 - of it by 5 ? 7. This question gives the number of years = — 40 ; and the equation being modified accordingly, we find that the question should have been : How many years after marriage was his age to hers as 7 to 6' 8. If - represent the fraction, the question gives
Σελίδα 5 - 6. 1st 10s. ; 2d 7s. ; 3d 8s. ; 4th 5s. ; 5th 3s. ; 6th 2s. 7. Smaller 40 galls. ; larger 80 galls. 8. Wheat 8s. ; rye 6s. per bushel. 9. 45 scholars in all. He wished to place 7 in a row. 10.
Σελίδα 28 - methods of elimination ; but they are all essentially the same, because they are all infinite. ART. 86. SECTION XXX. 1. 28. 5. 36. 2. 53. 6. 93. 3. 78. 7th and 8th performed. 4. 29. ART. 87.
Σελίδα 28 - 2 у = 10, in which the first members are identical, while the second members are different. Hence, the two conditions are incompatible with each other. By subtracting and canceling the terms containing y, we have 3
Σελίδα 27 - C's — $2000. Hence, either С is in debt $2000 ; or he possesses $2000. and a certain number of times his estate is subtracted, in each case, instead of being added. ART. 85. SECTION XXIX. 1. Let
Σελίδα 31 - SECTION XXXVI 3. 5 and 10. 4. Length 30, depth 8, breadth 22 feet. 5. 16 feet. • 6. 18 feet. 7. 6 and 12. 8. 22-071 + inches. 9. Side of the base
Σελίδα 55 - represent the known amount of their money, which is 5 . 32 or $160. In the first game A loses the whole amount minus his own share, or
Σελίδα 5 - SECTION IV. 1st, 2d, 3d, performed. 4. 60 years old. 20 years in Germany ; 15 in France ; 24 in England. 5. Whole estate $5040. He
Σελίδα 28 - Hence, the value of x is indeterminate; consequently, their ages cannot be ascertained from the conditions. 3. If z represent the number killed to-day, and