 | 1867 - 964 σελίδες
...to show. The reader will remember that in Problem XXIV (page 308) it was shown that triangles on the same base and between the same parallels are equal to one another, and that triangles on equal bases and between the same parallels are also equal to one another. Now... | |
 | John Playfair - 1806 - 320 σελίδες
...also the parallelogram ABCD is equal to EFGH. Wherefore, parallelograms, &c. QED PROP. XXXVII. THEOR. TRIANGLES upon the same base, and between the same parallels, are equal to one another. Let the triangles ABC, DEC be upon the same base BC, and between the same parallels AD, BC; the triangle... | |
 | Robert Simson - 1806 - 546 σελίδες
...parallelogram ABCD is equal to EFGH. Wherefore, parallelograms, &c. QED An ; . PROP. XXXVII. THEOR. TRIANGLES upon the same base, and between the same parallels, are equal to one another. Let the triangles ABC, DBC be upon the same base RC"and between the same parallels AD, BC : the triangle... | |
 | John Mason Good - 1813 - 714 σελίδες
...diameter bisects them, that is, divides them in two equal parts. Prop. XXXV. Theor. Parallelograms upon the same base and between the same parallels, are equal to one another. Prop. XXXVI. Theor. Parallelograms upon equal basis, and between the same parallels, are equal to one... | |
 | Euclides - 1816 - 588 σελίδες
...also the parallelogram ABCD is equal to EFGH. Wherefore parallelograms, &c. QED PROP. XXXVII. THEOR. TRIANGLES upon the same base, and between the same parallels, are equal to one another. Let the triangles ABC, DBC, be upon the same base BC, and between thesame p \ r\ parallels AD, BC :... | |
 | John Playfair - 1819 - 354 σελίδες
...the parallelogram ABCD is equal to EFGH. Wherefore, parallelograms, &c. Q, ED PROP. XXXVII. THEOR. Triangles upon the same base, and between the same parallels, are equal to one another. AD Let the triangles ABC, DBC be upon the same base BC, and between the same parallels AD, BC : The... | |
 | Peter Nicholson - 1825 - 1046 σελίδες
...divides the parallelogram ACDB into two eqoal parts, QED Proposition XXXV. Theorem. Parallelograms upon the same base, and between the same parallels, are equal to one another. Let the parallelograms ABCD, EBCF be upon the same base BC, and between the same parallels AF BC ;... | |
 | Euclid - 1826 - 234 σελίδες
...shall the two trapeziums be equal to one another. PROPOSITION XXXVII. THEOREM. Triangles constituted upon the same base, and between the same parallels, are equal to one another. Let the triangles ABC, DBC, be constituted upon the same base вс, and between the same parallels... | |
 | Euclides - 1826 - 226 σελίδες
...shall the two trapeziums be equal to one another. PROPOSITION XXXVII. THEOREM. Triangles constituted upon the same base, and between the same parallels, are equal to one another. » 3i. i. parallel to сл, " and through c draw CF, parallel to в D. Therefore each of them EBCA,... | |
 | Robert Simson - 1827 - 546 σελίδες
...diameter BC divides the parallelogram ACDB into two equal parts.' ei. ED PROP. XXXV. THEOR. Parallelograms upon the same base, and between the same parallels, are equal to one another. Let the parnllelograms ABCD, EBCF be upon the same base BC, and between the same parallels AF, BC :... | |
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TRIANGLES upon the same base, and between the same parallels, are equal to one another. 
