Elements of Euclid Adapted to Modern Methods in GeometryWilliam Collins, Sons,, 1874 - 216 σελίδες |
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Αποτελέσματα 1 - 5 από τα 39.
Σελίδα 12
... meet . Parallel lines are manifestly equidistant at all parts , and a moment's consideration will shew that two straight lines on different planes , although they are not parallel , may yet never meet ( see Prop . 14 , sch . ) . 25. A ...
... meet . Parallel lines are manifestly equidistant at all parts , and a moment's consideration will shew that two straight lines on different planes , although they are not parallel , may yet never meet ( see Prop . 14 , sch . ) . 25. A ...
Σελίδα 28
... meet another line AB A- obliquely in the point O , the perpendicular PF , from P , will fall at the side of the acute angle ; for , if not , POF , which is acute B ( hyp . ) , would be greater , being exterior , than the remote angle ...
... meet another line AB A- obliquely in the point O , the perpendicular PF , from P , will fall at the side of the acute angle ; for , if not , POF , which is acute B ( hyp . ) , would be greater , being exterior , than the remote angle ...
Σελίδα 31
... meet the opposite side . 2. By letting fall a perpendicular from any angle on the opposite side . Cor . - Hence the difference of any two sides of a triangle is less than the third side . For since AB and BC are greater than AC , if BC ...
... meet the opposite side . 2. By letting fall a perpendicular from any angle on the opposite side . Cor . - Hence the difference of any two sides of a triangle is less than the third side . For since AB and BC are greater than AC , if BC ...
Σελίδα 37
... meet either towards A and C , or B and D. Let them meet towards B and D in the point K ; then KFG will be a triangle , and AFG will be an exterior angle , and therefore greater than the angle FGD ; but AFG is equal to FGD , therefore it ...
... meet either towards A and C , or B and D. Let them meet towards B and D in the point K ; then KFG will be a triangle , and AFG will be an exterior angle , and therefore greater than the angle FGD ; but AFG is equal to FGD , therefore it ...
Σελίδα 38
... meet in K ; then the two angles BFG , FGD , taken together , are less than two right angles ; ( I. 13. ) ( Hyp . ) but they are equal to two right angles , therefore , taken together , they are both equal to two right angles , and less ...
... meet in K ; then the two angles BFG , FGD , taken together , are less than two right angles ; ( I. 13. ) ( Hyp . ) but they are equal to two right angles , therefore , taken together , they are both equal to two right angles , and less ...
Άλλες εκδόσεις - Προβολή όλων
Elements of Euclid Adapted to Modern Methods in Geometry Euclid,James Bryce,David Munn (F.R.S.E.) Δεν υπάρχει διαθέσιμη προεπισκόπηση - 1874 |
Συχνά εμφανιζόμενοι όροι και φράσεις
AC and CB altitude angle AOB BA and AC bisecting the angle centre chord circles touch circumference cloth coincide Const conv Cor.-Hence diagonal diameter divided draw equal angles equal to BC equal to twice equiangular equilateral triangle Euclid exterior angle Fcap GEOGRAPHY geometrical given circle given line given point given straight line greater half the perimeter Hence hypotenuse inscribed intersecting isosceles triangle less Let ABC LL.D meet middle point multiple opposite sides parallel to BC parallelogram perpendicular polygon produced Proposition Q. E. D. Cor Q. E. D. PROP radius ratio rectangle contained rectilineal figure reflex angle remaining angles required to prove right angles right-angled triangle schol segments shew shewn side BC square on AC tangent THEOREM triangle ABC twice the rectangle twice the square whole line
Δημοφιλή αποσπάσματα
Σελίδα 68 - The straight line joining the middle points of two sides of a triangle is parallel to the third side, and equal to half of it.
Σελίδα 77 - If there be two straight lines, one of which is divided into any number of parts, the rectangle contained by the two straight lines is equal to the rectangles contained by the undivided line, and the several parts of the divided line.
Σελίδα 50 - If a parallelogram and a triangle be upon the same base, and between the same parallels; the parallelogram is double of the triangle.
Σελίδα 87 - If a straight line be divided into two equal, and also into two unequal parts, the squares on the two unequal parts are together double of the square on half the line and of the square on the line between the points of section.
Σελίδα 30 - Any two sides of a triangle are together greater than the third side.
Σελίδα 204 - Tin; rectangle, contained by the diagonals of a quadrilateral inscribed in a circle, is equal to the sum of the rectangles contained by its opposite sides. Let ABCD be any quadrilateral inscribed in a circle...
Σελίδα 89 - To divide a given straight line into two parts, so that the rectangle contained by the whole and one of the parts, shall be equal to the square on the other part.
Σελίδα 98 - Guido, with a burnt stick in his hand, demonstrating on the smooth paving-stones of the path, that the square on the hypotenuse of a right-angled triangle is equal to the sum of the squares on the other two sides.