Higher Arithmetic: Designed for the Use of High Schools, Academies, and CollegesBennett, Backus & Hawley, 1841 - 252 σελίδες |
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Σελίδα 7
... partial payments are made on notes , bonds , etc. , Given the time , rate per cent . , and interest , to find the principal , Principal , time , and interest given to find the per cent . , Principal , rate per cent . , and interest , to ...
... partial payments are made on notes , bonds , etc. , Given the time , rate per cent . , and interest , to find the principal , Principal , time , and interest given to find the per cent . , Principal , rate per cent . , and interest , to ...
Σελίδα 13
... partial product : Secondly , repeating 3 + 2 as many times as there are units in 5 , we get ( 3 + 2 ) × 5 = 15 + 10 , for second partial product : Hence , 3 + 2 repeated as many times as there are units in 4 + 5 , becomes ( 3 + 2 ) ...
... partial product : Secondly , repeating 3 + 2 as many times as there are units in 5 , we get ( 3 + 2 ) × 5 = 15 + 10 , for second partial product : Hence , 3 + 2 repeated as many times as there are units in 4 + 5 , becomes ( 3 + 2 ) ...
Σελίδα 23
... partial products thus obtained will be the divisors sought . Examples . 1. What are the divisors of 48 ? Here we find 48 = 24 × 3. Therefore our series of terms will be 1 + 2 + 4 + 8 + 16 and 1 + 3 , multiplying these togeth- er ( by ...
... partial products thus obtained will be the divisors sought . Examples . 1. What are the divisors of 48 ? Here we find 48 = 24 × 3. Therefore our series of terms will be 1 + 2 + 4 + 8 + 16 and 1 + 3 , multiplying these togeth- er ( by ...
Σελίδα 53
... partial product 227364 . Secondly . We multiply 0.3789 , which is the multiplicand deprived of its right - hand ... partial product . Thirdly . Multiplying 0.378 by 4 , observing to carry 4 , we obtain 1516 for the third partial product ...
... partial product 227364 . Secondly . We multiply 0.3789 , which is the multiplicand deprived of its right - hand ... partial product . Thirdly . Multiplying 0.378 by 4 , observing to carry 4 , we obtain 1516 for the third partial product ...
Σελίδα 54
... partial product . 2. Multiply 0.3785 by 0.4673 . OPERATION . 0.3785 0.4673 15140 2271 265 11 Ans . 0.17687 3. What is the product of 0.00524486 by 0.99993682 ? OPERATION . 0.00524486 0.99993682 4720374 472037 47204 4720 157 31 4 Ans ...
... partial product . 2. Multiply 0.3785 by 0.4673 . OPERATION . 0.3785 0.4673 15140 2271 265 11 Ans . 0.17687 3. What is the product of 0.00524486 by 0.99993682 ? OPERATION . 0.00524486 0.99993682 4720374 472037 47204 4720 157 31 4 Ans ...
Άλλες εκδόσεις - Προβολή όλων
Συχνά εμφανιζόμενοι όροι και φράσεις
1st column acre Alligation amount of $1 annex annuity approximative values arithmetical progression bushel canceling carats cents per pound ciphers common difference compound interest continued fraction cube root decimal figures denominate values denoting diameter diminished dividend dollars equivalent fraction example we find exponent find the number following RULE frac fraction is equivalent geometrical progression gives greatest common measure half the number Hence improper fraction inches individual things interest of $1 last term least common multiple less lowest terms miles mixed number multiplied number is equivalent number of individual number of terms numerator and denominator obtain old progression OPERATION partial fraction perfect repetend places of decimals present worth prime factors prime numbers quantity quotient rate per cent ratio Reduce remainder rule under Art second figure second term shillings simple fraction SOLUTION square root subtract third term total branches trial divisor vulgar fraction weeks whole number wine
Δημοφιλή αποσπάσματα
Σελίδα 35 - Then multiply all the numerators together for a new numerator, and all the denominators together for a new denominator...
Σελίδα 96 - Add to the first term the product of the common difference into the number of terms less one, and the sum will be the last term.
Σελίδα 164 - To raise a whole number or a decimal to any power, use it as a factor as many times as there are units in the exponent.
Σελίδα 98 - Hence, when the extremes and number of terms are given, to find the common difference, — Divide the difference of the extremes by the number of terms, less 1, and the quotient will be the common difference.
Σελίδα 173 - From the above proposition, it follows that the square of the hypotenuse, diminished by the square of one of the sides, equals the square of the other side. By means of these properties, it follows that two sides of a right-angled triangle being given, the third side can be found. Examples. 1. How long must a ladder be, to reach the top of a house, 40 feet high, when the foot of it is 30 feet from the house ? In this example it is obvious that the ladder forms the hypotenuse of a right-angled triangle,...
Σελίδα 30 - To reduce fractions to a common denominator, we have this RULE. Reduce mixed numbers to. improper fractions — compound fractions to their simplest form. Then multiply each numerator by all the denominators, except its own, for a new numerator, and all the denominators together for a common denominator. It is obvious that this process will give the same denominator to each fraction, viz : the product of all the denominators. It is also obvious that the values of the fractions will not be...
Σελίδα 139 - DISCOUNT is an allowance made for the payment of money before it is due. The present worth of a...
Σελίδα 91 - A wall was to be built 700 yards long in 29 days; after 12 men had been employed on it for 11 days, it was found they had built only 220 yards. How many more men must be put on, to finish it in the given time ? 54.
Σελίδα 91 - In how many days, working 9 hours a day, will 24 men dig a trench 420 yards long, 5 yards wide, and 3 yards deep, if 248 men, working...
Σελίδα 97 - Given the first term, last term, and common difference, to find the number of terms. RULE. — Divide the difference of the extremes by the common difference, and the quotient increased by 1 is the number of terms.