Higher Arithmetic: Designed for the Use of High Schools, Academies, and CollegesBennett, Backus & Hawley, 1841 - 252 σελίδες |
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Σελίδα 3
... expressed my approbation of the plan to the author while he was preparing the manuscript ; and now that I have given the work a somewhat thorough examination , I am happy to say not only that my former opinion of its plan is confirmed ...
... expressed my approbation of the plan to the author while he was preparing the manuscript ; and now that I have given the work a somewhat thorough examination , I am happy to say not only that my former opinion of its plan is confirmed ...
Σελίδα 6
... expressed , to determine the number of decimals , When the decimals do not terminate they recur in periods , Simple and mixed repetends , Perfect repetends , Method of decimating when many figures are required , Method of decimating by ...
... expressed , to determine the number of decimals , When the decimals do not terminate they recur in periods , Simple and mixed repetends , Perfect repetends , Method of decimating when many figures are required , Method of decimating by ...
Σελίδα 12
... expression , 11 + 5-2 = 2x7 = 28 ÷÷ 2 = 14 , when translated into common language , becomes the sum of 11 and 5 diminished by 2 equals the product of 2 and 7 , equals 28 divided by 2 , equals 14 . 2. The expression , ( 42-8 ) 2 + 3 ...
... expression , 11 + 5-2 = 2x7 = 28 ÷÷ 2 = 14 , when translated into common language , becomes the sum of 11 and 5 diminished by 2 equals the product of 2 and 7 , equals 28 divided by 2 , equals 14 . 2. The expression , ( 42-8 ) 2 + 3 ...
Σελίδα 13
... expression is equivalent to the following ? - " Three times twenty - one , increased by five times seven , and diminished by three times the square of four , is equal to twice the square of five ? " 9. What expression is equivalent to ...
... expression is equivalent to the following ? - " Three times twenty - one , increased by five times seven , and diminished by three times the square of four , is equal to twice the square of five ? " 9. What expression is equivalent to ...
Σελίδα 14
... 500 + 30 +4 . Now 70000 = 9999 × 7 + 7 8000 500 999 × 8 + 8 99X5 + 5 30 = = 9 × 3 + 3 す +4 78534 = 9999 × 7 + 999 × 8 + 99 × 5 + 9 × 3 + ( 7 + 8 + 5 + 3 + 4 . ) Now , since each expression , 9999 × 7 , · 14 HIGHER ARITHMETIC .
... 500 + 30 +4 . Now 70000 = 9999 × 7 + 7 8000 500 999 × 8 + 8 99X5 + 5 30 = = 9 × 3 + 3 す +4 78534 = 9999 × 7 + 999 × 8 + 99 × 5 + 9 × 3 + ( 7 + 8 + 5 + 3 + 4 . ) Now , since each expression , 9999 × 7 , · 14 HIGHER ARITHMETIC .
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Συχνά εμφανιζόμενοι όροι και φράσεις
1st column acre Alligation amount of $1 annex annuity approximative values arithmetical progression bushel canceling carats cents per pound ciphers common difference compound interest continued fraction cube root decimal figures denominate values denoting diameter diminished dividend dollars equivalent fraction example we find exponent find the number following RULE frac fraction is equivalent geometrical progression gives greatest common measure half the number Hence improper fraction inches individual things interest of $1 last term least common multiple less lowest terms miles mixed number multiplied number is equivalent number of individual number of terms numerator and denominator obtain old progression OPERATION partial fraction perfect repetend places of decimals present worth prime factors prime numbers quantity quotient rate per cent ratio Reduce remainder rule under Art second figure second term shillings simple fraction SOLUTION square root subtract third term total branches trial divisor vulgar fraction weeks whole number wine
Δημοφιλή αποσπάσματα
Σελίδα 35 - Then multiply all the numerators together for a new numerator, and all the denominators together for a new denominator...
Σελίδα 96 - Add to the first term the product of the common difference into the number of terms less one, and the sum will be the last term.
Σελίδα 164 - To raise a whole number or a decimal to any power, use it as a factor as many times as there are units in the exponent.
Σελίδα 98 - Hence, when the extremes and number of terms are given, to find the common difference, — Divide the difference of the extremes by the number of terms, less 1, and the quotient will be the common difference.
Σελίδα 173 - From the above proposition, it follows that the square of the hypotenuse, diminished by the square of one of the sides, equals the square of the other side. By means of these properties, it follows that two sides of a right-angled triangle being given, the third side can be found. Examples. 1. How long must a ladder be, to reach the top of a house, 40 feet high, when the foot of it is 30 feet from the house ? In this example it is obvious that the ladder forms the hypotenuse of a right-angled triangle,...
Σελίδα 30 - To reduce fractions to a common denominator, we have this RULE. Reduce mixed numbers to. improper fractions — compound fractions to their simplest form. Then multiply each numerator by all the denominators, except its own, for a new numerator, and all the denominators together for a common denominator. It is obvious that this process will give the same denominator to each fraction, viz : the product of all the denominators. It is also obvious that the values of the fractions will not be...
Σελίδα 139 - DISCOUNT is an allowance made for the payment of money before it is due. The present worth of a...
Σελίδα 91 - A wall was to be built 700 yards long in 29 days; after 12 men had been employed on it for 11 days, it was found they had built only 220 yards. How many more men must be put on, to finish it in the given time ? 54.
Σελίδα 91 - In how many days, working 9 hours a day, will 24 men dig a trench 420 yards long, 5 yards wide, and 3 yards deep, if 248 men, working...
Σελίδα 97 - Given the first term, last term, and common difference, to find the number of terms. RULE. — Divide the difference of the extremes by the common difference, and the quotient increased by 1 is the number of terms.