Modern Methods in Elementary GeometryMacmillan, 1868 - 112 σελίδες |
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Αποτελέσματα 1 - 5 από τα 15.
Σελίδα 6
... turned about BC so that A may fall on A ' . Then , since ADB is a right angle , ADB + BDA ' = 2R . Therefore ADA ' is a straight line , Whence AA ' < AE + EA ' . I. 3 . Therefore , AD < AE . Also AE + EA 6 ELEMENTARY GEOMETRY .
... turned about BC so that A may fall on A ' . Then , since ADB is a right angle , ADB + BDA ' = 2R . Therefore ADA ' is a straight line , Whence AA ' < AE + EA ' . I. 3 . Therefore , AD < AE . Also AE + EA 6 ELEMENTARY GEOMETRY .
Σελίδα 13
... fall between D and B , as at C ' . Then the exterior angle AC'D is greater than ABD ; that is , C > B. Conversely , if the angle C be greater than the angle B , then shall AB be greater than AC . COR . If the angle C be equal to the ...
... fall between D and B , as at C ' . Then the exterior angle AC'D is greater than ABD ; that is , C > B. Conversely , if the angle C be greater than the angle B , then shall AB be greater than AC . COR . If the angle C be equal to the ...
Σελίδα 15
... fall on A'B ' . Then because AB = A'B ' , B will coincide with B ' . And , because the angle B = the angle B ' , BC will take the direction of B'C ' . And , because BC = B'C ' , the point C will coincide with the point C ' . Therefore ...
... fall on A'B ' . Then because AB = A'B ' , B will coincide with B ' . And , because the angle B = the angle B ' , BC will take the direction of B'C ' . And , because BC = B'C ' , the point C will coincide with the point C ' . Therefore ...
Σελίδα 23
... fall GE , GH perpendicular to AB , AC . And let GE meet AD in P ; let fall PF perpendicular to AC , and join GF . Then GH < GF , < GP + PF , [ I. 5 . but Therefore PF = PE . GH < GE . Hence AD is the locus of a point equally distant ...
... fall GE , GH perpendicular to AB , AC . And let GE meet AD in P ; let fall PF perpendicular to AC , and join GF . Then GH < GF , < GP + PF , [ I. 5 . but Therefore PF = PE . GH < GE . Hence AD is the locus of a point equally distant ...
Σελίδα 24
E. M. Reynolds. being measured by perpendiculars let fall from a point in AD , AB and AC are equally remote from AD , the distance being measured along a line perpendicular to AD . For , B GP -D F joining EF , each to each , and EA , AG ...
E. M. Reynolds. being measured by perpendiculars let fall from a point in AD , AB and AC are equally remote from AD , the distance being measured along a line perpendicular to AD . For , B GP -D F joining EF , each to each , and EA , AG ...
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A'BC Algebra alternate angle altitude angle equal arc CD ARITHMETIC bisect BROOKE FOSS WESTCOTT Cambridge centre circle touching circumference cloth coincide congruent CONIC SECTIONS contain convex angle convex polygon Crown 8vo diagonals diameter dicular divide duplicate ratio Edward Thring ELEMENTARY TREATISE equal angles equally distant equally remote equiangular equiangular and similar equilateral triangle Examples exterior angle Fcap Find the locus GEOMETRY given angle given circle given line given point given straight line greater Hence intersect isosceles John's College late Fellow Let ABCD line drawn MATHEMATICAL measure meet middle point opposite sides parallel to BC parallelogram perpen perpendicular polygon produced quadrilateral figure radius rectangle right angles right-angled triangle Schools Second Edition segments Shew shortest line similar triangles student subtend tangent THEOREM THEOREM VII Third Edition trapezium triangle ABC vertex