The young ladies' new guide to arithmetic


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Σελίδα 54 - Thirty days hath September, April, June, and November, All the rest have thirty-one Excepting February alone : Which hath but twenty-eight, in fine, Till leap year gives it twenty-nine.
Σελίδα 62 - Then multiply the second and third terms together, and divide the product by the first term: the quotient will be the fourth term, or answer.
Σελίδα 9 - I = One. II = Two. III = Three. IV = Four. V = Five. VI = Six. VII = Seven. VIII = Eight. IX = Nine. X = Ten. XI = Eleven.
Σελίδα 44 - PROOF. Multiply the divisor and quotient together, and to the product add the remainder, if any; if the result be equal to the dividend, the work is correct.
Σελίδα 50 - APOTHECARIES' WEIGHT 20 grains = 1 scruple. 3 scruples = 1 dram. 8 drams = 1 ounce. 12 ounces = 1 pound.
Σελίδα 62 - Then, if from the nature of the question the number sought should be larger than the third term, place the greater of the two remaining terms for the second term, and the less for the first, but if the...
Σελίδα 75 - Multiply the principal by the rate per cent, and divide the product by 100 ; the quotient will be the answer.
Σελίδα 9 - XX, Twenty. XXX, Thirty. XL, Forty. L, Fifty. LX, Sixty. LXX, Seventy. LXXX, Eighty. XC, Ninety. C, One hundred.
Σελίδα 43 - Find how many times the divisor is contained in the first figure, or figures, of the dividend, and, setting it directly under the dividend, carry the remainder, if any, to the next figure as so many tens.
Σελίδα 87 - To find the number of days between the given day of any month, in the same year ; suppose from the 20th of March, to the 24th of August following. Find the number answering to the 24th of August, (viz. 236) from which subtract the number answering to the 20th of March (79) there remains 157 the number required. 4. To find the number of days from a given day of one month, to the given day of another month in the next year ; suppose from the 10th of October, to the 6th of April in the following year....

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