Elements of GeometryGinn and Heath, 1877 - 250 σελίδες |
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Αποτελέσματα 1 - 5 από τα 22.
Σελίδα 21
... point in a perpendicular , cut off equal distances from the foot of the perpendicular . C A B E F K Let C F be the perpendicular , and C E and C K be two equal oblique lines drawn from the point ... middle PERPENDICULAR AND OBLIQUE LINES .
... point in a perpendicular , cut off equal distances from the foot of the perpendicular . C A B E F K Let C F be the perpendicular , and C E and C K be two equal oblique lines drawn from the point ... middle PERPENDICULAR AND OBLIQUE LINES .
Σελίδα 22
... middle of the straight line A B , O any point in P R , and C any point without PR . I. Draw OA and O B. We are to prove OA = 0 B. Since - PA PB , OA = OB , ов , § 53 ( two oblique lines drawn from the same point in a 1 , cutting off ...
... middle of the straight line A B , O any point in P R , and C any point without PR . I. Draw OA and O B. We are to prove OA = 0 B. Since - PA PB , OA = OB , ов , § 53 ( two oblique lines drawn from the same point in a 1 , cutting off ...
Σελίδα 23
... point is a line , straight or curved , con- taining all the points which possess a common property . Thus , the perpendicular erected at the middle of a straight line is the locus of all points equally distant from the extremi- ties of ...
... point is a line , straight or curved , con- taining all the points which possess a common property . Thus , the perpendicular erected at the middle of a straight line is the locus of all points equally distant from the extremi- ties of ...
Σελίδα 27
... middle point of B C , draw A D1 to G H. Then AD is likewise to E F , ( a straight line to one of two lls is to the other ) , that is , CD and BA are both L to A D. § 67 Apply figure COD to figure BOA so that OD shall fall on O A. Then ...
... middle point of B C , draw A D1 to G H. Then AD is likewise to E F , ( a straight line to one of two lls is to the other ) , that is , CD and BA are both L to A D. § 67 Apply figure COD to figure BOA so that OD shall fall on O A. Then ...
Σελίδα 34
... points in AB , as E and H , let EF and HK be drawn perpendicular to A B. We are to prove EF = HK . Now EF and HK are to CD , ( a line to one of two lls is to the other also ) . Let M be the middle point of EH . Draw MP 1 to A B. $ 67 On ...
... points in AB , as E and H , let EF and HK be drawn perpendicular to A B. We are to prove EF = HK . Now EF and HK are to CD , ( a line to one of two lls is to the other also ) . Let M be the middle point of EH . Draw MP 1 to A B. $ 67 On ...
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Συχνά εμφανιζόμενοι όροι και φράσεις
A B C AABC AACB ABCD adjacent angles alt.-int altitude apothem arc A B bisect centre circumference circumscribed coincide COROLLARY describe an arc diagonals diameter divided Draw equal arcs equal distances equal respectively equiangular polygon equilateral equilateral polygon exterior angles figure given line given point given polygon given straight line greater homologous sides hypotenuse isosceles triangle Let A B Let ABC limit line A B measured by arc middle point number of sides parallelogram perimeter perpendicular plane PROBLEM prove Q. E. D. PROPOSITION quadrilateral radii radius equal ratio rect rectangles regular inscribed regular polygon required to construct rhombus right angles right triangle SCHOLIUM segment sides of equal sides of similar similar polygons subtend tangent THEOREM third side triangle ABC variable vertex vertices