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194. Miscellaneous Review.

1. A piece of land in the form of an equilateral triangle measures on one side 46 rods. What is the distance around it?

2. The perimeter of a piece of land that is an exact square is 2463 feet. How far across on one side?

3. The length of a certain rectangular field is three times its breadth; its perimeter is 360 rd. What is its breadth? Its length?

4. If of the value of a farm is $2154, what is of the value of the farm?

NOTE. If of a certain number is 24, what is the number? What is of the number?

5. I spent of my money and had $3.60 remaining. (a) How much did I spend? (b) What I had remaining, equals what part of what I spent?

6. Change to an equivalent fraction whose denominator is 30.

7. Change to an equivalent fraction whose numerator is 30.

8. Change

nator is bc.

9. Multiply

a2

to an equivalent fraction whose denomi

b

by 3 and multiply the product by 25.

10. Multiply 37 by 13 and multiply the product by 25.

11. If 3 of an acre of land is worth $36, how much are 37 acres worth at the same rate?

12. The rent of a house for 2 yr. 4 mo. was $840. What was the rate per year?

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From the foregoing operations the following rules for dividing by a fraction are obtained:

RULE I. Reduce the dividend and the divisor to like fractional units, then divide the numerator of the dividend by the numerator of the divisor.

RULE II. "Invert the divisor and proceed as in multiplication."

Observe that the inverted divisor shows the number of times the divisor is contained in 1: then in 6 it is contained 6 times as many times; in 4, 4 times as many; in, as many; in, as many, etc.

*18 thirds + 2 thirds = 9.
†13. 3 thirds + 2 thirds = 1} = }.

35 fortieths + 24 fortieths = 111. 21. 5 fifths + 3 fifths = 13 = §.

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IV. Find the quotient. (See page 246, problem 33.)

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Fractions.

196. TO REDUCE COMPLEX FRACTIONS TO SIMPLE

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FRACTIONS.

7

is read, divided by .= 2 of ;= 24 = 4.

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3

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Observe that a complex fraction may be reduced to a simple fraction by multiplying its numerator and denominator by some number that will in each case give an integral product. When this number can be easily discovered by inspection this is a convenient method of reduction: thus

7

X2 1

7 × 2

=

14'

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