Practical and Mental Arithmetic on a New Plan: In which Mental Arithmetic is Combined with the Use of the Slate : Containing a Complete System for All Practical Purposes Being in Dollars and CentsRichardson & Lord, 1829 - 268 σελίδες |
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Σελίδα 21
... hence its introduction into our own country . Q. About what time was it introduced into England ? A. About the mid- dle of the eleventh century . Q. How extensively is it now used ? A. All over the ofvilized world . As you have probably ...
... hence its introduction into our own country . Q. About what time was it introduced into England ? A. About the mid- dle of the eleventh century . Q. How extensively is it now used ? A. All over the ofvilized world . As you have probably ...
Σελίδα 40
... hence the 5 must be placed in the tens ' place . 13140 days , Ans . To explain why you add the two products together . What does multiplying 365 by 6 give ? A. The number of days in 6 years . What does multiplying 365 by 3 tens give ? A ...
... hence the 5 must be placed in the tens ' place . 13140 days , Ans . To explain why you add the two products together . What does multiplying 365 by 6 give ? A. The number of days in 6 years . What does multiplying 365 by 3 tens give ? A ...
Σελίδα 41
... hence the value is increased 10 times . What effect would two ciphers have , or three ciphers , & c . ? A. Two ciphers would remove any figure two places towards the left , and of course increase it 100 times , and so on for 1000 , & c ...
... hence the value is increased 10 times . What effect would two ciphers have , or three ciphers , & c . ? A. Two ciphers would remove any figure two places towards the left , and of course increase it 100 times , and so on for 1000 , & c ...
Σελίδα 55
... hence , when the cents are less than 10 , they must occupy the units ' place of cents , and a cipher the tens ' place of cents . Q. In writing down mills with dollars , when there are no cents , how many ciphers must you place between ...
... hence , when the cents are less than 10 , they must occupy the units ' place of cents , and a cipher the tens ' place of cents . Q. In writing down mills with dollars , when there are no cents , how many ciphers must you place between ...
Σελίδα 77
... Hence , to divide by 51 , 304 , & c . , we need only bring the divisor into halves , quarters , & c . , also the dividend into the same , and the quotient will be the answer . 29. In 132 yards how many rods ? In 4224 yards ? A. 792 rods ...
... Hence , to divide by 51 , 304 , & c . , we need only bring the divisor into halves , quarters , & c . , also the dividend into the same , and the quotient will be the answer . 29. In 132 yards how many rods ? In 4224 yards ? A. 792 rods ...
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2d power 50 cents acres amount apiece apples barrel bbls breadth broadcloth bushels called ciphers cloth cost common difference common fraction compound interest contained cord feet corn cube root cubic currency decimal decimal places derive the following divide dividend divisor dollars equal example Exercises federal money feet long feet wide following RULE foot gain gallons greatest common divisor hence hogshead illustrations we derive improper fraction least common multiple leaves length lowest terms miles mills mixed number molasses months multiply Note number of terms OPERATION ounces payment pence pints pound present worth principal proceed proportion pupil quantity quotient figure rate per cent ratio Reduce remainder shillings side Slate solid feet solid inches square feet square rods square root subtract third term whole number write yards of cloth