 | John Davidson, Robert Scott (writing master) - 1818 - 190 σελίδες
...also on the right of the divisor ; multiply the divisor thus completed ly this nea figure, suUnii.t the product from the dividend, and to the remainder annex the next fart for a new dividend. To the complete divisor add the last figure of the reot, the turn will be... | |
 | George Roberts Perkins - 1841 - 274 σελίδες
...; the result will be the TRUE DIVISOR. Multiply the true divisor by this second figure of the root, and subtract the product from the dividend, and to the remainder annex the next period,for a SECCUD DIVIDEND. . ft IV. To the last TRUE DIVISOR, add the Jastfgure of the root, for... | |
 | John Husband (math. master, Berwick.) - 1841 - 126 σελίδες
...together these two lines for the complete divisor; multiply the sum by the second figure in the root ; subtract the product from the dividend, and to the remainder annex the third period for a new dividend. Place the square of the second figure of the root under the complete... | |
 | 1843 - 142 σελίδες
...product write also the square of the trial-figure, then multiply the sum of these by the trial-figure, subtract the product from the dividend, and to the...remainder annex the next period for a new dividend. EVOLUTION.ciphers for a new divisor, with which find anolner trialfigure, and proceed as before. 1.... | |
 | George Roberts Perkins - 1846 - 266 σελίδες
...; the result will be the TRUE DIVISOR. Multiply the true divisor by this second figurt of the root, and subtract the product from the dividend, and to the remainder annex the next period, for a SECOND DIVIDEND. IV. To the last TRUE DIVISOR, add the last figure of the not, for a new TRIAL DIVISOR,... | |
 | George Roberts Perkins - 1849 - 346 σελίδες
...DIVISOR ; the result will be the TRUE DIVISOR. Multiply the true divisor by this last figure of the root, and subtract the product from the dividend, and to...remainder annex the next period, for a NEW DIVIDEND. IV. To the last TRUE DIVISOR add the last figure of the root ; the sum, with a cipher annexed, will... | |
 | Rufus Putnam - 1849 - 402 σελίδες
...down the next period for a dividend . 4 . Multiply the complete divisor by the last figure m the root, subtract the product from the dividend, and to the...remainder annex the next period for a new dividend. If the product should exceed the dividend, diminish the last figure of the root, and of the complete... | |
 | George Roberts Perkins - 1849 - 344 σελίδες
...; the result will be the TRUE DIVISOR. Multiply the true divisor by this second figure of the root, and subtract the product from the dividend, and to the remainder annex the next period for a SECOND DIVIDEND. operate as before, until all the periods have been brought down. EXAMPLES. 1. What... | |
 | George Roberts Perkins - 1849 - 356 σελίδες
...the last term of the 2d column. Again, multiply this last result by this second figure of the root, and subtract the product from the dividend, and to the remainder annex tlie next period for a NEW DIVIDEND. Proceed with this second figure of the root precisely as was done... | |
 | George Roberts Perkins - 1850 - 364 σελίδες
...DIVISOR ; the result will be the TRUE DIVISOR. Multiply the true divisor by this last figure of the root, and subtract the product from the dividend, and to...remainder annex the next period, for a NEW DIVIDEND. 1 V. To the last TRUE DIVISOR add the last figure of the root ; the sum, with a cipher annexed, will... | |
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... subtract the product from the dividend, and to the remainder annex the next period for the next dividend. 
