 | 1801 - 658 σελίδες
...30 • Or 6 : i :: 28,2744 : 4-7124 Or 3 : 30 :: -05236X9 : 4'7^4 36 4-7124 the answer. RULE a.* . From 8 times the chord of half the arc subtract the chord of the whole arc, and ~ of the remainder "-'ill be the length of the arc nearly. 2. The * DEMONSTRATION. Let the radius OD~r, and... | |
 | Anthony Nesbit, W. Little - 1822 - 916 σελίδες
...French iaticians, to 128. PROBLEM XII. To Jtnd the length of the arc of a circle. RULE I. By the Pen. 8 times the chord of half the arc subtract the chord of the whole ate, and i of the remainder will be the length of the arc, nearly. Note 1. Half the chord of the whole... | |
 | Anthony Nesbit - 1824 - 476 σελίδες
...Bonnycastle's As* 'ronomy, page 277. PROBLEM XIV. To find the length of any arc of a circle. RULE I. From 8 times the chord of half the arc subtract the chord of the whole arc, and }, of the remainder . will be the length of the arc, nearly. Kote. Half the chord of the whole arc, the chord... | |
 | John Nicholson - 1825 - 822 σελίδες
...180 : 30 Or 6 : 1 : : 282744 : 47124 Or 3 : 39 : : '05236 x 9 : 47124 90 47124 the answer. Rule 2. From 8 times the chord of half the arc subtract the chord of the whole arc, and ' of the remainder will be the length of viie arc nearly. Ex. 2. The chord AB (Proli. 8.) of the whole arc being... | |
 | John Nicholson (civil engineer.) - 1825 - 1008 σελίδες
...: 30 Or 6 : 1 : : 282744 : 47124 Or 3 : 30 : : '05236 X 9 : 4-7124 90 4*7124 the answer. R'i!,- 2. From 8 times the chord of half the arc subtract the chord of tbe whole arc, and ' of the remainder will be the length of the arc nearly. Ex. 2. The chord AB (Prol.... | |
 | William Galbraith - 1827 - 412 σελίδες
...radius of the circle multiplied by 0.0174533 and by the number of degrees in the arc. Or, from eight times the chord of half the arc subtract the chord of the whole arc, one third of this remainder is the length of the arc nearly. 9. Circular Sector. — The area is equivalent... | |
 | John Nicholson (Civil engineer) - 1830 - 240 σελίδες
...As 180 : 30 Or 6 : 1 : : 282744 : 47124 Or 3: 30 : : 105236 x 9:47124 90 47124 the answer. Rule 2. From 8 times the chord of half the arc subtract the chord of the whole arc, and .1 of the remainder will be the length of the arc nearly. Ex. 2. The chord AB (Prob. 8.) of the whole... | |
 | John Nicholson (Esq. Civil Engineer.) - 1831 - 432 σελίδες
...180 : 30 Or6 : 1 : : 282744:4.7124 Or 3 : 30 : : .05236 X 9 : 4.7124 90 4.7124 the answer. Rule 2. From 8 times the chord of half the arc subtract the chord of the whole arc, and I of the remainder will be the length of the arc nearly. Ex. 2. The chord AB, (Prob. 8,) of the whole... | |
 | Francis Walkingame - 1833 - 204 σελίδες
...5. The area X'6S6G197) Problem 9- Toßnd the length of a circular arc RULE 1. From 8 times Fig. 8. the chord of half the arc subtract the chord of the...difference will be the length of the arc, nearly. That is ADx8— AB -т-3=.агс ADB. NOTE. Half the chord of the whole arc, the chord of half the... | |
 | Olinthus Gregory - 1834 - 484 σελίδες
...4400 Add } s* = 80 Area of the dodecagon = 4480 : the true area is 4478-46. 3. Length of circular arc. From 8 times the chord of half the arc, subtract the chord of the whole arc, and 4 of the remainder will be the length of the arc, nearly. Note. — The chord of half the arc is equal... | |
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Or, from 8 times the chord of half the arc, subtract the chord of the whole arc, and $ of the remainder will be the length of the arc, nearly. 
