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" The logarithm of a quotient is equal to the logarithm of the dividend minus the logarithm of the divisor. "
An Algebra for High Schools and Academies - Σελίδα 384
των Louis Parker Jocelyn - 1902 - 445 σελίδες
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The elements of plane trigonometry

John Charles Snowball - 1837 - 322 σελίδες
...logarithm is the sum of the logarithms of the several factors, we obtain the product of those factors. 5. The logarithm of a quotient is equal to the logarithm...of the dividend minus the logarithm of the divisor. For a " =-=V n a1a?1 .-. la (— I => la»и- \аП. \П I r log I - J = log m — log n. Hence, if...

A Treatise on Trigonometry, and on Trigonometrical Tables and Logarithms ...

John Hymers - 1841 - 244 σελίδες
...generally, that the logarithm of a product is equal to the sum of the logarithms of its factors. 8. The logarithm of a quotient is equal to the logarithm of the dividend diminished by that of the divisor. ч 102 Since m - o*, n — а", та* .-.-=— = а-', n а? •'•...

Mathematical Dictionary and Cyclopedia of Mathematical Science: Comprising ...

Charles Davies, William Guy Peck - 1855 - 628 σελίδες
...the factors, taken separately. 2. The logarithm of the quotient of one number by another, is ci/ual to the logarithm of the dividend, minus the logarithm of the divisor. 3. The logarithm of any power oj a. quantity, is equal to the product of the logarithm of the quantity...

Elements of Algebra: On the Basis of M. Bourdon, Embracing Sturm's and ...

Charles Davies - 1857 - 408 σελίδες
...I -— 1 ; that is, The logarithm of the quotient which arises from dividing one number by another is equal to the logarithm of the dividend minus the logarithm of the divisor. 232i If we raise both members of equation (1) to the «'* power, we have, a*.' = N'n (5). But from...

A Treatise on Plane and Spherical Trigonometry, and on Trigonometrical ...

John Hymers - 1858 - 324 σελίδες
...generally, that the logarithm of any product is equal to the sum of the logarithms of its factors. 8. The logarithm of a quotient is equal to the logarithm of the dividend diminished by that of the divisor. Since m — a", n = a", m a_ i fm\ ii .'' S" (n) = X~y= g" m ~ g°...

Algebra

Isaac Todhunter - 1858 - 530 σελίδες
...therefore m= a", n = d?; therefore m/n - aa* = a'+'; therefore log, mn - x + y = log. m + log„ n. 53G. The logarithm of a quotient is equal to the logarithm of the dividend diminished by the logarithm of the divisor. For let x — log. m, y = log. n ; therefore m = a', therefore...

Algebra for High Schools and Colleges: Containing a Systematic Exposition ...

James B. Dodd - 1859 - 368 σελίδες
...then and, by substituting these values in the last logarithmic equation, we have, considering that the logarithm of a quotient is equal to the logarithm...of the dividend minus the logarithm of the divisor, log. (»+i>- log. B=2ar(^+^^+-pL—5.+fa,. ;)or log (w+1)= log. w+2M(-Li + 3-^-j. -H This last equation...

Elements of Algebra: On the Basis of M. Bourdon, Embracing Sturm's and ...

Charles Davies - 1860 - 412 σελίδες
...definition, j that is, The logarithm of the quotient which arises from dividing on' number by another is equal to the logarithm of the dividend minus the logarithm of the divisor. 232i If we raise both members of equation (1) to the n'* power, we have, a«' = N'a ..... (5). But...

Elements of Algebra: On the Basis of M. Bourdon, Embracing Sturm's and ...

Charles Davies - 1860 - 412 σελίδες
...(N' \ -]yr)-> that is, The logarithm of the quotient which arises from dividing one number by another is equal to the logarithm of the dividend minus the logarithm of tin divisor. 232t If we raise both members of equation (1) to the nth power, we have, But from the...

Elements of Geometry and Trigonometry: With Practical Applications

Benjamin Greenleaf - 1862 - 518 σελίδες
...Multiplying equations, member by member, we have Therefore, log (MX N) =. x -\-y = log M+ log N. 10. The logarithm of a QUOTIENT is equal to the logarithm of the dividend diminished by tftat of the divisor. For, by Art. 9, we have M=a*, N=a". * Dividing the first equation...




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