An Introduction to Algebra Upon the Inductive Method of InstructionCummings, Hilliard, 1826 - 276 σελίδες |
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Σελίδα 140
... root of which is 7. I subtract 49 from 53 , and bring down the next two figures , which makes 438. Now considering ... 3d . Bring down the two next figures at the right of the remain- der . Double the root already found for a divisor ...
... root of which is 7. I subtract 49 from 53 , and bring down the next two figures , which makes 438. Now considering ... 3d . Bring down the two next figures at the right of the remain- der . Double the root already found for a divisor ...
Σελίδα 155
... root . 327 × 327 × 327 34,965,783 . Therefore the result is correct . If the root consists of four or more places ... 3d power of 300 7,965,783 ( 270,000 { 1st divisor = 300 X 300 X 3 -32,768,000 3d power of 320 2d divid . 2,197,783 ...
... root . 327 × 327 × 327 34,965,783 . Therefore the result is correct . If the root consists of four or more places ... 3d power of 300 7,965,783 ( 270,000 { 1st divisor = 300 X 300 X 3 -32,768,000 3d power of 320 2d divid . 2,197,783 ...
Σελίδα 156
... 3d power and subtract it from 34 , as if it stood alone . Then , to form the divisor , hun- dreds are multiplied by hundreds , therefore there can be no significant figure below 10000. And it being the tens of the root that are to be ...
... 3d power and subtract it from 34 , as if it stood alone . Then , to form the divisor , hun- dreds are multiplied by hundreds , therefore there can be no significant figure below 10000. And it being the tens of the root that are to be ...
Σελίδα 160
... root of a whole number which is not a perfect third power , may be approximated by converting the number into a ... 3d power of 1 1 1st dividend = 3d power of 1.7 40 ( 3 1st divisor . 4.913 2d dividend = 870 8700 ( 867 2d do . 3 X ( 17 ) ...
... root of a whole number which is not a perfect third power , may be approximated by converting the number into a ... 3d power of 1 1 1st dividend = 3d power of 1.7 40 ( 3 1st divisor . 4.913 2d dividend = 870 8700 ( 867 2d do . 3 X ( 17 ) ...
Σελίδα 170
... 3d . Take the root of both members . The root of the first member will be a binomial , the first term of which will be the unknown quantity , and the second will be half the coefficient of x as found above . The root of the second ...
... 3d . Take the root of both members . The root of the first member will be a binomial , the first term of which will be the unknown quantity , and the second will be half the coefficient of x as found above . The root of the second ...
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Άλλες εκδόσεις - Προβολή όλων
An Introduction to Algebra: Upon the Inductive Method of Instruction Warren Colburn Πλήρης προβολή - 1837 |
An Introduction to Algebra Upon the Inductive Method of Instruction Warren Colburn Πλήρης προβολή - 1831 |
An Introduction to Algebra upon the Inductive Method of Instruction Warren Colburn Πλήρης προβολή - 1844 |
Συχνά εμφανιζόμενοι όροι και φράσεις
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