An Introduction to Algebra Upon the Inductive Method of InstructionCummings, Hilliard, 1826 - 276 σελίδες |
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Σελίδα 9
... expression . ( + ) A cross , one line being horizontal and the other per- pendicular , signifies " added to . " " added to . " It may be read and , more , plus , or any similar expression ; thus , 7+ 5 = 12 , is read 7 and 5 are 12 , or ...
... expression . ( + ) A cross , one line being horizontal and the other per- pendicular , signifies " added to . " " added to . " It may be read and , more , plus , or any similar expression ; thus , 7+ 5 = 12 , is read 7 and 5 are 12 , or ...
Σελίδα 10
... expressed in the form of a fraction ( Arith . Art . XVI . Part II . ) , the divisor being made the denominator , and the dividend the numerator . Thus 15 = 5 , is read 15 divided by 3 is equal to 5 , or one third of 15 , is 5 , or 15 ...
... expressed in the form of a fraction ( Arith . Art . XVI . Part II . ) , the divisor being made the denominator , and the dividend the numerator . Thus 15 = 5 , is read 15 divided by 3 is equal to 5 , or one third of 15 , is 5 , or 15 ...
Σελίδα 13
... expression which shall be equal to a given quantity , and then from that , by arithmetical operations , to deduce the value of the unknown quantity . This expression of equality between two quantities , is called an equation . In the ...
... expression which shall be equal to a given quantity , and then from that , by arithmetical operations , to deduce the value of the unknown quantity . This expression of equality between two quantities , is called an equation . In the ...
Σελίδα 26
... expressed or understood , may be removed from one member to the other by giving it the sign ; for this is the same as subtracting it from both sides . Thus x + 3 = 10 ; x is not so much as 10 by 3 , we therefore say x = 103 . Again , 5 ...
... expressed or understood , may be removed from one member to the other by giving it the sign ; for this is the same as subtracting it from both sides . Thus x + 3 = 10 ; x is not so much as 10 by 3 , we therefore say x = 103 . Again , 5 ...
Σελίδα 30
... expressed x + 25 2 Hence we have Multiplying by 2 , By transposing x and -70 , Uniting terms , Dividing by 5 , 3x- 35 = 6 х 6 x - --- x + 25 2 · 70 = x + 25 x 25+ 70 x = 25 + 70 5x95 x = 19 B's age . A's age . x + 25 = 44 Note . Since ...
... expressed x + 25 2 Hence we have Multiplying by 2 , By transposing x and -70 , Uniting terms , Dividing by 5 , 3x- 35 = 6 х 6 x - --- x + 25 2 · 70 = x + 25 x 25+ 70 x = 25 + 70 5x95 x = 19 B's age . A's age . x + 25 = 44 Note . Since ...
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Άλλες εκδόσεις - Προβολή όλων
An Introduction to Algebra: Upon the Inductive Method of Instruction Warren Colburn Πλήρης προβολή - 1837 |
An Introduction to Algebra Upon the Inductive Method of Instruction Warren Colburn Πλήρης προβολή - 1831 |
An Introduction to Algebra upon the Inductive Method of Instruction Warren Colburn Πλήρης προβολή - 1844 |
Συχνά εμφανιζόμενοι όροι και φράσεις
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