An Introduction to Algebra Upon the Inductive Method of InstructionCummings, Hilliard, 1826 - 276 σελίδες |
Αναζήτηση στο βιβλίο
Αποτελέσματα 1 - 5 από τα 35.
Σελίδα 7
... formulas , to see what values the unknown quantities will take for particular suppositions made upon the known ... formula for equations of the second degree XXXV . Demonstration of the principle that every equation of the second ...
... formulas , to see what values the unknown quantities will take for particular suppositions made upon the known ... formula for equations of the second degree XXXV . Demonstration of the principle that every equation of the second ...
Σελίδα 56
... formulas . It is easy to see the propriety of the rule . For the formula -b 55. 13 42 shows , that if the $ 13 that A pays α- or 2 - 2 - 2 ' more than B , be taken out , the remainder is to be paid in equal parts by them . Also the formula ...
... formulas . It is easy to see the propriety of the rule . For the formula -b 55. 13 42 shows , that if the $ 13 that A pays α- or 2 - 2 - 2 ' more than B , be taken out , the remainder is to be paid in equal parts by them . Also the formula ...
Σελίδα 57
... formula for the greatest part . α 26 с b , or b subtracted from + + thus ; or 00 or + x = b = 3 x = b = a + X- b = α - The least part is x α 3 x — b .b -- - + - 3 с α 3 8160 3 3 3 ' 26 + 3 110022100 26 b 3 3 + + b b 813 3 - 3 0100 010 + ...
... formula for the greatest part . α 26 с b , or b subtracted from + + thus ; or 00 or + x = b = 3 x = b = a + X- b = α - The least part is x α 3 x — b .b -- - + - 3 с α 3 8160 3 3 3 ' 26 + 3 110022100 26 b 3 3 + + b b 813 3 - 3 0100 010 + ...
Σελίδα 58
... formula , is 16000 + 2 × 2000+ 1000 = 7000 crowns . 3 The other shares may be found by the other two formulas . Let the learner solve this question by making x equal to the less part , and also by making it equal to the mean . Exam ...
... formula , is 16000 + 2 × 2000+ 1000 = 7000 crowns . 3 The other shares may be found by the other two formulas . Let the learner solve this question by making x equal to the less part , and also by making it equal to the mean . Exam ...
Σελίδα 59
... formula is expressed in words as follows : Di- vide the price of the whole by the price of a bushel of each sort added together , and it will give the number of bushels of each sort . 9. A father dying left $ 25000 ( or a ) to be ...
... formula is expressed in words as follows : Di- vide the price of the whole by the price of a bushel of each sort added together , and it will give the number of bushels of each sort . 9. A father dying left $ 25000 ( or a ) to be ...
Περιεχόμενα
13 | |
66 | |
74 | |
76 | |
80 | |
86 | |
89 | |
95 | |
195 | |
197 | |
202 | |
208 | |
217 | |
221 | |
226 | |
228 | |
102 | |
121 | |
122 | |
142 | |
150 | |
159 | |
175 | |
186 | |
193 | |
Άλλες εκδόσεις - Προβολή όλων
An Introduction to Algebra: Upon the Inductive Method of Instruction Warren Colburn Πλήρης προβολή - 1837 |
An Introduction to Algebra Upon the Inductive Method of Instruction Warren Colburn Πλήρης προβολή - 1831 |
An Introduction to Algebra upon the Inductive Method of Instruction Warren Colburn Πλήρης προβολή - 1844 |
Συχνά εμφανιζόμενοι όροι και φράσεις
12 rods 3d power a b c A's share a² b² a² b³ ac² added algebra algebraic quantities answer the conditions apiece apples approximate root Arith arithmetic becomes binomial Binomial Theorem bought breadth bushels cents coefficient compound interest compound quantities contain decimal denominator difference divide the number dividend divisor equal equation example exponent expression factor find the root formula fourth fraction gallons gives greater Hence less letter logarithm merator miles multiplicand negative quantity number consisting number of dollars number of terms observe pears quan question quotient remainder required to find rule second power second root shillings sold square rods subtracted Suppose third power third root tities twice unknown quantity whole number yards zero