Designing Valve GearingE. & F.N. Spon, 1875 - 283 σελίδες |
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Αποτελέσματα 1 - 5 από τα 60.
Σελίδα 1
... a circle , of which B C is a diameter and E the centre ; and draw CA , dividing the circle into the segments A B C , A DC , and join BA , A D , DC : the angle in the semicircle BAC shall be a B right angle ; but the angle in the segment A.
... a circle , of which B C is a diameter and E the centre ; and draw CA , dividing the circle into the segments A B C , A DC , and join BA , A D , DC : the angle in the semicircle BAC shall be a B right angle ; but the angle in the segment A.
Σελίδα 2
... Join A E , and produce B A to F. Then , because EA is equal to EB ( Euc . I. Defi- nition 15 ) , the angle E AB is equal to the angle EBA ( Euc . I. 5 ) ; and , because EA is B E C equal to EC , the angle EA C is equal to the angle ECA ...
... Join A E , and produce B A to F. Then , because EA is equal to EB ( Euc . I. Defi- nition 15 ) , the angle E AB is equal to the angle EBA ( Euc . I. 5 ) ; and , because EA is B E C equal to EC , the angle EA C is equal to the angle ECA ...
Σελίδα 19
... Join EA and produce it till it again cuts the circle B D M C in a point F. Upon EA and AF as diameters describe the valve- circles E L V and FWT , these will be the primary ` and secondary valve - circles respectively , and A E c 2 ...
... Join EA and produce it till it again cuts the circle B D M C in a point F. Upon EA and AF as diameters describe the valve- circles E L V and FWT , these will be the primary ` and secondary valve - circles respectively , and A E c 2 ...
Σελίδα 28
... Join AK , and from the centre A describe a circle , V ZR , touching the line Q L R K G Fig . 8 . PK at the point Z , this circle , V Z R , will be the lap- circle . From P and K , as centres , describe arcs inter- secting at the point 0.
... Join AK , and from the centre A describe a circle , V ZR , touching the line Q L R K G Fig . 8 . PK at the point Z , this circle , V Z R , will be the lap- circle . From P and K , as centres , describe arcs inter- secting at the point 0.
Σελίδα 29
... Join ER and EL ( Fig . 8 ) , which will be perpendicular to AK and AD respectively ( Euclid III . 31 ) . Draw DF parallel to K Z. Join DH , which will of course be equal to FZ . Then in the triangles E A R , KAZ , we have EA equal to AK ...
... Join ER and EL ( Fig . 8 ) , which will be perpendicular to AK and AD respectively ( Euclid III . 31 ) . Draw DF parallel to K Z. Join DH , which will of course be equal to FZ . Then in the triangles E A R , KAZ , we have EA equal to AK ...
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Συχνά εμφανιζόμενοι όροι και φράσεις
amount equal amount of lead Bisect brought into gear central position centre line close the port crank reaches crossed rods cutting the arc cutting the line cylinder dead-point describe arcs intersecting describe the arc describe the circle diameter describe divides the arc eccentric rods engine Euclid EXPANSION GEARING expansion valve find the point find the throw full gear given amount given position intersecting the line Join length line A B link diagram link-motion main valve circle main valve eccentric MCNP motion open an amount open rods parallel perpendicular point E point F posi position relative primary main valve Problem proportion radius equal radius rod radius vector reaches the position real position represent the centre represent the position represent the throw required to find right angles shaft single virtual eccentric slider spindle steam-port Stephenson's straight line throw and position triangle valve eccentric sheave valve gear valve-spindle virtual eccentric arm
Δημοφιλή αποσπάσματα
Σελίδα 2 - BAC shall be a right angle; and the angle in the segment ABC, which is greater than a semicircle, shall be less than a right angle ; and the angle in the segment ADC, which is less than a semicircle, shall be greater than a right angle. Join AE, and produce BA to F.
Σελίδα 3 - ABC must be less than a right angle : and therefore the angle in a segment ABC greater than a semicircle, is less than a right angle. And...
Σελίδα 1 - The angle in a semicircle is a right angle; the angle in a segment greater than a semicircle is less than a right angle; and the angle in a segment less than a semicircle is greater than a right angle.