Designing Valve GearingE. & F.N. Spon, 1875 - 283 σελίδες |
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Αποτελέσματα 1 - 5 από τα 49.
Σελίδα 12
... diagram we may , as we have already explained , assume that the line A D is the centre line of the crank , and cause it to revolve about the point A , through the same angular distance as the real centre line of the crank is supposed ...
... diagram we may , as we have already explained , assume that the line A D is the centre line of the crank , and cause it to revolve about the point A , through the same angular distance as the real centre line of the crank is supposed ...
Σελίδα 14
... diagram , that AD represents this position of the crank ; we have also shown that the valve has to move an amount equal to AQ before it commences to open the port , and in order , therefore , to find that position of the crank , at ...
... diagram , that AD represents this position of the crank ; we have also shown that the valve has to move an amount equal to AQ before it commences to open the port , and in order , therefore , to find that position of the crank , at ...
Σελίδα 15
... diagram ( Fig . 4 ) we have already shown that the valve commences to open the port when the crank is in the position AK , we can in like manner show that the valve just closes the port when the centre line of the crank reaches the ...
... diagram ( Fig . 4 ) we have already shown that the valve commences to open the port when the crank is in the position AK , we can in like manner show that the valve just closes the port when the centre line of the crank reaches the ...
Σελίδα 21
... diagram . Returning , however , to the method of applying the diagram , AD is the ( assumed ) position of the crank , when A E represents the centre line of the eccentric sheave , this crank revolving in the direction indicated by the ...
... diagram . Returning , however , to the method of applying the diagram , AD is the ( assumed ) position of the crank , when A E represents the centre line of the eccentric sheave , this crank revolving in the direction indicated by the ...
Σελίδα 23
... diagram ( Fig . 6 ) we made QL equal to the lead that was given . Following the crank as it revolves , we find that when it has reached the position A X the port is open an amount equal to U J , and when in the position AE the port is ...
... diagram ( Fig . 6 ) we made QL equal to the lead that was given . Following the crank as it revolves , we find that when it has reached the position A X the port is open an amount equal to U J , and when in the position AE the port is ...
Άλλες εκδόσεις - Προβολή όλων
Συχνά εμφανιζόμενοι όροι και φράσεις
amount equal amount of lead Bisect brought into gear central position centre line close the port crank reaches crossed rods cutting the arc cutting the line cylinder dead-point describe arcs intersecting describe the arc describe the circle diameter describe divides the arc eccentric rods engine Euclid EXPANSION GEARING expansion valve find the point find the throw full gear given amount given position intersecting the line Join length line A B link diagram link-motion main valve circle main valve eccentric MCNP motion open an amount open rods parallel perpendicular point E point F posi position relative primary main valve Problem proportion radius equal radius rod radius vector reaches the position real position represent the centre represent the position represent the throw required to find right angles shaft single virtual eccentric slider spindle steam-port Stephenson's straight line throw and position triangle valve eccentric sheave valve gear valve-spindle virtual eccentric arm
Δημοφιλή αποσπάσματα
Σελίδα 2 - BAC shall be a right angle; and the angle in the segment ABC, which is greater than a semicircle, shall be less than a right angle ; and the angle in the segment ADC, which is less than a semicircle, shall be greater than a right angle. Join AE, and produce BA to F.
Σελίδα 3 - ABC must be less than a right angle : and therefore the angle in a segment ABC greater than a semicircle, is less than a right angle. And...
Σελίδα 1 - The angle in a semicircle is a right angle; the angle in a segment greater than a semicircle is less than a right angle; and the angle in a segment less than a semicircle is greater than a right angle.