Designing Valve GearingE. & F.N. Spon, 1875 - 283 σελίδες |
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Αποτελέσματα 1 - 5 από τα 41.
Σελίδα 6
... parallel to B A , and A P is equal to MF ; therefore AP also represents the distance the valve has travelled from its central posi- tion A towards D , whilst the centre of the eccentric sheave has moved from B to F ; and if we consider ...
... parallel to B A , and A P is equal to MF ; therefore AP also represents the distance the valve has travelled from its central posi- tion A towards D , whilst the centre of the eccentric sheave has moved from B to F ; and if we consider ...
Σελίδα 7
... parallel to the virtual direction of motion of the valve , the exact distance that the valve has tra- velled from its central position for that particular angular advance of the eccentric sheave ; and if the centre of the sheave is ...
... parallel to the virtual direction of motion of the valve , the exact distance that the valve has tra- velled from its central position for that particular angular advance of the eccentric sheave ; and if the centre of the sheave is ...
Σελίδα 29
... perpendicular to AK and AD respectively ( Euclid III . 31 ) . Draw DF parallel to K Z. Join DH , which will of course be equal to FZ . Then in the triangles E A R , K A Z , we have EA equal to AK , and the angle SIMPLE VALVE GEAR . 29.
... perpendicular to AK and AD respectively ( Euclid III . 31 ) . Draw DF parallel to K Z. Join DH , which will of course be equal to FZ . Then in the triangles E A R , K A Z , we have EA equal to AK , and the angle SIMPLE VALVE GEAR . 29.
Σελίδα 33
... parallel to A B. It will now be quite clear that , in the position NS of the crank , the port will be open an amount TP , and this position re- presents the given position CI , because NS is par- allel to CI , both being at right angles ...
... parallel to A B. It will now be quite clear that , in the position NS of the crank , the port will be open an amount TP , and this position re- presents the given position CI , because NS is par- allel to CI , both being at right angles ...
Σελίδα 34
... parallel to CD , both being at right angles to CE . Again the port is opened an amount V Q , when the piston com ... parallel to A V , and VQ being drawn parallel to A C , must also be equal to it . To find the point N , it is only ...
... parallel to CD , both being at right angles to CE . Again the port is opened an amount V Q , when the piston com ... parallel to A V , and VQ being drawn parallel to A C , must also be equal to it . To find the point N , it is only ...
Άλλες εκδόσεις - Προβολή όλων
Συχνά εμφανιζόμενοι όροι και φράσεις
amount equal amount of lead Bisect brought into gear central position centre line close the port crank reaches crossed rods cutting the arc cutting the line cylinder dead-point describe an arc describe arcs intersecting describe the arc describe the circle diameter describe divides the arc eccentric rods engine Euclid EXPANSION GEARING expansion valve find the point find the throw full gear given amount given position intersecting the line Join length link diagram link-motion main valve circle main valve eccentric MCNP motion open an amount open rods parallel perpendicular point E point F position relative primary main valve Problem proportion radius equal radius rod radius vector reaches the position real position represent the centre represent the position represent the throw required to find respectively right angles shaft single virtual eccentric slider spindle steam-port Stephenson's throw and position triangle valve eccentric sheave valve gear valve-spindle virtual eccentric arm
Δημοφιλή αποσπάσματα
Σελίδα 2 - BAC shall be a right angle; and the angle in the segment ABC, which is greater than a semicircle, shall be less than a right angle ; and the angle in the segment ADC, which is less than a semicircle, shall be greater than a right angle. Join AE, and produce BA to F.
Σελίδα 3 - ABC must be less than a right angle : and therefore the angle in a segment ABC greater than a semicircle, is less than a right angle. And...
Σελίδα 1 - The angle in a semicircle is a right angle; the angle in a segment greater than a semicircle is less than a right angle; and the angle in a segment less than a semicircle is greater than a right angle.