Designing Valve GearingE. & F.N. Spon, 1875 - 283 σελίδες |
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Αποτελέσματα 1 - 5 από τα 31.
Σελίδα
... presents the greatest difficulty to the designer . To meet this , many of our leading mathematicians have propounded definite formulæ for determining the due proportionment of the various parts ; but while these of course ultimately ...
... presents the greatest difficulty to the designer . To meet this , many of our leading mathematicians have propounded definite formulæ for determining the due proportionment of the various parts ; but while these of course ultimately ...
Σελίδα 3
... present pur- pose , however , the prin- ciple may be enunciated as follows : - B Fig . 1 . If from either end B or C , ( Fig . 1 ) , of the dia- meter B C of the circle A B C , a straight line B F be drawn cutting the circumference in ...
... present pur- pose , however , the prin- ciple may be enunciated as follows : - B Fig . 1 . If from either end B or C , ( Fig . 1 ) , of the dia- meter B C of the circle A B C , a straight line B F be drawn cutting the circumference in ...
Σελίδα 5
... present the cen- tre of the eccen- N tric sheave when the valve is in the middle of its travel , for the Fig . 2 . theoretical deviation from this point , caused by the angular motion of the eccentric rod , is really so small as to be ...
... present the cen- tre of the eccen- N tric sheave when the valve is in the middle of its travel , for the Fig . 2 . theoretical deviation from this point , caused by the angular motion of the eccentric rod , is really so small as to be ...
Σελίδα 21
... present the centre line of the sheave , if the real position of the crank were represented by the line A D , in both cases of course the crank and eccentric sheave would be revolving in the opposite direction to the arrows in the ...
... present the centre line of the sheave , if the real position of the crank were represented by the line A D , in both cases of course the crank and eccentric sheave would be revolving in the opposite direction to the arrows in the ...
Σελίδα 22
... presents that position of the crank at which the valve just commences to open the port and admit steam into the cylinder . We will next suppose the crank to have reached the position AD , AL will now be the radius vector , deducting ...
... presents that position of the crank at which the valve just commences to open the port and admit steam into the cylinder . We will next suppose the crank to have reached the position AD , AL will now be the radius vector , deducting ...
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Συχνά εμφανιζόμενοι όροι και φράσεις
amount equal amount of lead Bisect brought into gear central position centre line close the port crank reaches crossed rods cutting the arc cutting the line cylinder dead-point describe arcs intersecting describe the arc describe the circle diameter describe divides the arc eccentric rods engine Euclid EXPANSION GEARING expansion valve find the point find the throw full gear given amount given position intersecting the line Join length line A B link diagram link-motion main valve circle main valve eccentric MCNP motion open an amount open rods parallel perpendicular point E point F posi position relative primary main valve Problem proportion radius equal radius rod radius vector reaches the position real position represent the centre represent the position represent the throw required to find right angles shaft single virtual eccentric slider spindle steam-port Stephenson's straight line throw and position triangle valve eccentric sheave valve gear valve-spindle virtual eccentric arm
Δημοφιλή αποσπάσματα
Σελίδα 2 - BAC shall be a right angle; and the angle in the segment ABC, which is greater than a semicircle, shall be less than a right angle ; and the angle in the segment ADC, which is less than a semicircle, shall be greater than a right angle. Join AE, and produce BA to F.
Σελίδα 3 - ABC must be less than a right angle : and therefore the angle in a segment ABC greater than a semicircle, is less than a right angle. And...
Σελίδα 1 - The angle in a semicircle is a right angle; the angle in a segment greater than a semicircle is less than a right angle; and the angle in a segment less than a semicircle is greater than a right angle.