 | Thomas Sherwin - 1841 - 314 σελίδες
...divide the first term of the dividend, and place the quotient, with its proper sign, as the second term of the root, also at the right of the divisor. Multiply the divisor, with the term annexed, by the second term of the root, and subtract the product from the dividend. 4. The remainder... | |
 | Elias Loomis - 1846 - 376 σελίδες
...already found, and annex the result both to the root and the divisor. Multiply the divisor thus increased by the last term of the root, and subtract the product from the last remainder. Proceed in the same manner to find the additional terms of the root. Ex. 1. Required the... | |
 | Elias Loomis - 1846 - 380 σελίδες
...already found, and annex the result both to the root and the divisor. Multiply the divisor thus increased by the last term of the root, and subtract the product from the last remainder. Proceed in the same manner to find the additional terms of the root. Ex. 1. Required the... | |
 | Elias Loomis - 1855 - 356 σελίδες
...of the two terms of the root, and the square of the second term. Multiply the divisor thus increased by the last term of the root, and subtract the product from the last remainder. Proceed in the same manner to find the additional terms of the root. Ex. 1. Extract the... | |
 | Thomas Sherwin - 1856 - 318 σελίδες
...second term of the root, and subtract the product from the dividend. 4. The remainder will form a new dividend, which is to be divided by twice the whole...last term of the root, and subtract the product from tlie last dividend. 5. The remainder will form a new dividend, with which proceed as before ; and thus... | |
 | Elias Loomis - 1856 - 280 σελίδες
...divisor, and annex the result both to the root and the divisor. 5. Multiply the divisor thus increased by the last term of the root, and subtract the product from the last remainder. Proceed in the same manner to find the additional terms of the root. Ex. 1. Required the... | |
 | Theodore Strong - 1859 - 570 σελίδες
...the second correction, to the sum, and the divisor will be completed. Multiply the complete divisor by the last term of the root, and subtract the product from the first remainder ; then the result will constitute the second remainder. 3. To the preceding complete... | |
 | Thomas Sherwin - 1841 - 318 σελίδες
...second term of the root, and subtract the product from the dividend. 4. The remainder will form a new dividend, which is to be divided by twice the whole...be placed as the next term of the root, also at the rigid of the divilor. Multiply the divisor, with the term last annexed, by the last term of the root,... | |
 | Thomas Sherwin - 1862 - 252 σελίδες
...given quantity. ART. 114. From the foregoing examples and explanations, we derive the following RULE FOR EXTRACTING THE SECOND ROOT OF A POLYNOMIAL. 1....as the next term of the root, also at the right of the*divisor. Multiply the divisor, with the term last annexed, by the last term of the root, and subtract... | |
 | Benjamin Greenleaf - 1863 - 338 σελίδες
...term by the last, and the square of the last, for a complete divisor. Multiply the complete divisor by the last term of the root, and subtract the product from the dividend. If there are other terms remaining, form a new dividend, and continue the operation in the... | |
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Multiply the divisor, with the term last annexed, by the last term of the root, and subtract the product from the last dividend. 
