 | Jeremiah Day - 1815 - 172 σελίδες
...the third side may be found, without the aid of the trigonometrical tables, by the proposition, that the square of the hypothenuse is equal to the sum of the squares of the two perpendicular sides. (Euc. 47. 1.) If the legs be given, extracting the square root... | |
 | Jeremiah Day - 1815 - 388 σελίδες
...referred to. 94. Other relations of the sine, tangent, Sic. may be derived from the proposition, that the square of the hypothenuse is equal to the sum of the squares of the perpendicular sides. (Euc. 47. I.) In the right angled triangles CBG, CAD, and CHF,... | |
 | Adrien Marie Legendre - 1819 - 574 σελίδες
...others ; for the three figures will be proportional to the squares of their homologous sides ; now the square of the hypothenuse is equal to the sum of the squares of the two other sides ; therefore, &c. THEOREM. 223. The parts of two chards which cut each... | |
 | William Nicholson - 1821 - 356 σελίδες
...to one another. In every right-angled triangle, the square of the hypothenuse is equal to the sum of the squares of the other two sides; and, in general,...the hypothenuse is equal to the sum of two similar figures described upon the two sides. In an isosceles triangle, that is, a triangle having two of its... | |
 | Frederick Beasley - 1822 - 584 σελίδες
...parallelograms be added together they will be equal to the smaller squares added together, or in other words, the square of the hypothenuse, is equal to the sum of the squares of the other sides. It will here be distinctly perceived, that the progress of the understanding... | |
 | Jeremiah Day - 1824 - 440 σελίδες
...the third side may be found, without the aid of the trigonometrical tables, by the proposition, that the square of the hypothenuse is equal to the sum of the squares of the two perpendicular sides (Euc. 47. I.) If the legs be given, extracting the square root... | |
 | Adrien Marie Legendre, John Farrar - 1825 - 280 σελίδες
...others ; for the three figures will be proportional to the squares of their homologous sides ; now the square of the hypothenuse is equal to the sum of the squares of the two other sides ; therefore, &c. THEOREM. 223. The parts of two chords which cut each... | |
 | Adrien Marie Legendre, John Farrar - 1825 - 294 σελίδες
...others ; for the three figures will be proportional to the squares of their homologous sides ; now the square of the hypothenuse is equal to the sum of the squares of the two other sides ; therefore, &c. V 223. The parts of two chords which cut each other... | |
 | Ferdinand Rudolph Hassler - 1826 - 208 σελίδες
...three sides ; to find the Surface of the triangle. By the theorem of geometry, so often employed : that the square of the hypothenuse is equal to the sum of the squares of the two sides, and expressing the parts by trigonometry, as in section 56, we find : BD... | |
 | Ferdinand Rudolph Hassler - 1826 - 640 σελίδες
...three sides; to find the Surface of the triangle. By the theorem of geometry, so often employed : that the square of the hypothenuse is equal to the sum of the squares of the two sides, and expressing the parts by trigonometry, as in section 56, we find : BD... | |
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... the square of the hypothenuse is equal to the sum of the squares of the other two sides. 
