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NOTE. — As half a foot is eqnal to 6 inches, we add them to the 5 inches, which make 11 inches.
12. From 67yd. 1qr. Ina. lin. take 18yd. 2qr. 2na. 2in.
Ans. 48yd. 2qr. 2na. 1fin. 13. From 51E.E. 2qr. 3na. take 19E.E. 3qr. Ina.
14. From 56A. 1R. 19p. 119ft. 110in. take 17A. 3R. 13p. 127ft. 113in.
Ans. 38A. 2R. 5p. 264ft. 33in. 15. Find the value of 13A. 1R. 15p. 19yd. 1ft. 17in. - 9A. 3R. 16p. 30yd. 5ft. 17in. 16. Subtract 19m. 2fur. 1ch. 3p. 211. from 21m. 1fur. 3ch.
Ans. lm. 7fur. 1ch. 2p. 231. 17. From 28m. 6fur. 1ch. 2p. 181. take 15m. 7fur. 3ch. lp. 191.
18. Required the value of 49T. 13ft. 1611in. 18T. 15ft. 1719in.
Ans. 30T. 37ft. 1620in.
19. Required the value of 361C. 47ft. 1178in. 197C. 121ft. 1617in.
20. Subtract 11tun lhhd. 28gal. 2qt. 1 pt. from 79tun 3hhd. 19gal. Iqt. 1pt.
Ans. 68tun lbhd. 53 gal. 3qt. 21. Subtract of beer measure 191hhd. 19gal. 3qt. from 769hhd. 18gal. 1qt. 22. From 56ch. 2bu. lpk. take 38ch. 3bu. 1pk.
Ans. 17 ch. 35bu. 23. Required the value of 25bu. 3pk. 1qt. - 12bu. 3pk. 5qt.
Ans. 12bu. 3pk. 4qt. 24. Required the difference between 6mo. 16d. 13h. 27m. 19s. and 1mo. 22d. 16h. 41m. 37s.
Ans. 4mo. 23d. 20h. 45m. 42s. 25. From 48y. Omo. 15d. 19h. 27m. 31s. take 19y. 10mo. 29d. 21h. 38m. 56s. 26. From 6S. 11° 12' 48" subtract 9S. 8° 15' 56".
Ans. 9S. 2° 56' 52". 27. Take 1S. 22° 19' 28" from 4S. 19° 41' 22".
28. I have 73A. of land ; if I should sell 5 A. 3R. 1p. 7ft., how much should I have left ? Ans. 67A. OR. 38p. 265 ft.
29. A owes B 100£. ; what will remain due after he has paid him 3s. 6įd.?
Ans. 99£. 16s. 5 d. 30. It is about 25,000 miles round the globe ; if a man shall have travelled 43m. 17rd. 9in., how much will remain to be travelled ?
Ans. 24,956m. 7fur. 22rd. 15ft. Iin. 31. Bought 7 cords of wood; 2 cords 78ft. having been stolen, how much remained ?
32. I have 15 yards of cloth; having sold 3yd. 2qr. 1na., what remains ?
Ans. 1lyd. 1qr. 3na. 33. If a wagon loaded with hay weighs 43cwt. 2qr. 18lb., and the wagon is afterwards found to weigh 9cwt. 3qr. 23lb., what is the weight of the hay ? Ans. 33cwt. 2qr. 20lb.
34. Bought a hogshead of wine, and by an accident 8gal. 3qt. 1 pt. leaked out; what remains ?
35. I had 10A. 3R. 10p. of land; and I have sold two houselots, one containing 1A. 2R. 13p., the other 2A. 2R. 5p.; how much have I remaining ?
Ans. 6A. 2R. 32p. 36. The Moon moves 13° 10' 35" in a solar day, and the Sun 59' 8"'; now supposing them both to start from the
same point in the heavens, how far will the Moon have gained on the Sun in 24 hours ?
Ans. 12° 11' 27". 37. A farmer raised 136bu. of wheat; if he sells 49bu. 2pk. 7qt. lpt., how much has he remaining ?
Ans. 86bu. 1 pk. Oqt. 1 pt. 38. If from a stick of timber containing 2T. 18ft. 1410in. there be taken 38ft. 1720in., how much will be left?
Ans. 1T. 19ft. 1418in.
MULTIPLICATION OF COMPOUND NUMBERS.
147. MULTIPLICATION of Compound Numbers is the process of taking a compound number any proposed number of times.
Ex. 1. What will 6 bales of cloth cost, at 7£. 12s. 7d. per bale ?
Ans. 45£. 15s. 6d. Having written the multiplier under
the lowest denomination of the multiMultiplicand 7 12 7
plicand, we multiply_thus: 7d. X 6 Multiplier
6 42d. 3s. 6d. We write the 6d. Product 4 5 1 5 6
under the number multiplied, and re
serve the 3s. to be added to the product of the shillings. Then, 12s. X 6 = 728., and 3s. (carried) 75s. 3£. 15s. We write the 15s. under the column of shillings, and reserve the 3£. to be added to the product of the pounds. Again, 7£. X 6 42£., and 3£. (carried) = 45£. This, placed under the column of pounds, gives 45£. 15s. 6d.
RULE. Multiply each denomination of the compound number as in multiplication of simple numbers, and carry as in addition of compound numbers.
Proof. — Write down by themselves the several products obtained by multiplying each denomination of the multiplicand by the multiplier, and these partial products added together will equal the entire product, if the work be right. (Art. 60.)
NOTE. – Going a second time carefully over the work is a good way of testing its accuracy. On learning Division of Compound Numbers, the pupil will find that rule a better inethod of proving multiplication of compound aumbers.
2. Multiply 1£. 8s. 7d. 2far. by 7.
Ans. 10£. Os. 4d. 2far
PROOF BY ADDITION.
S. d. 2
9 d. X 8 76d. 0£. 6s. 4d. 8 8s.
64s. 3£. 4s. Od. Ans. 19 10 4 2£. x 8 16£. 16£. Os. Od.
2£. 8s. 94d. X 8
19£. 10s. 4d. NOTE. — The answers to the following examples may be found in correBponding numbers of examples in Division of Compound Numbers.
9. Multiply 16A. 2R. 4p. 19yd. 7ft. 79in. by 11. 10. Multiply 10yd. 3qr. 3na. by 5. 11. Multiply 17tun 2hhd. 50gal. Iqt. by 7. 12. Multiply 29hhd. 61gal. 3qt. 1pt. 3gi. by 7. 13. Multiply 19bu. 2pk. 7qt. 1pt. by 6. 14. What is the value of 13y. 316d. 15h. 27m. 39s. X 8? 15. Multiply 16deg. 39m. 3fur. 39rd. 5yd. 2ft. by 9.
16. If a man gives each of his 9 sons 23A. 3R. 193p., what do they all receive ?
17. If 12 men perform a piece of labor in 7h. 24m. 30s., how long would it take 1 man to perform the same task ?
18. If 1 bag contain 3bu. 2pk. 4qt., what quantity do 8 bags contain ?
148. When the multiplier is a composite number, and none of its factors exceed 12.
Ex. 1. What will 35 loads of coal weigh, if each load weighs 2T. lcwt. 2qr. 6lb. ?
We find the num
ber 35 equal to the 2 1 2 6 weight of 1 load.
product of 7 and 5; 7
we therefore multiply 14 10 3 17 = weight of 7 loads.
the weight of i load
by 7, and then that 5
product by 5; and the 7 2 14 2 10= weight of 35 loads. last product is the an
Hence, when the multiplier is a composite number,
Multiply by its factors in succession.
EXAMPLES. 2. Bought 90 hogsheads of sugar, each weighing 12cwt. 2qr. 11lb. ; what was the weight of the whole ?
3. What cost 18 sheep at 5s. 9 d. apiece ?
6. If 1 share in a certain stock be valued at 13£. 8s. 9fd., what is the value of 96 shares ?
7. If 1 spoon weighs 3oz. 5pwt. 15gr., what is the weight of 120 spoons ?
8. If a man travel 24m. 7fur. 4rd. in 1 day, how far will he go in 1 month ?
9. If the earth revolve 0° 15' per minute, how far does it revolve
hour? 10. Multiply 39A. 3R. 17p. 30yd. 8ft. 100in. by 32.
11. If a man be 2d. 5h. 17m. 19sec. in walking 1 degree, how long would it take him to walk round the earth, allowing 3657 days to a year?
149. When the multiplier is not a composite number, and exceeds 12; or when a composite number one of whose factors exceeds 12.
Ex. 1. What is the value of 453 tons of iron at 18£. 17s. 11d. a ton ?