The National Arithmetic on the Inductive System: Combining the Analytic and Synthetic Methods : Forming a Complete Course of Higher ArithmeticRobert S. Davis & Company, 1878 - 450 σελίδες |
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Σελίδα 34
... answer sought . - 2. John Drew has a yearly income of 2,500 dollars ; his family expenses are 1,300 dollars , his expenditures in improv- ing his estate 450 dollars , and his contributions to several worthy objects 225 dollars . What ...
... answer sought . - 2. John Drew has a yearly income of 2,500 dollars ; his family expenses are 1,300 dollars , his expenditures in improv- ing his estate 450 dollars , and his contributions to several worthy objects 225 dollars . What ...
Σελίδα 45
... answers to the product , and the divisor and quotient to the factors , of multiplication . In multiplication , two factors are given , to find their product ; and in division , one of two factors and their product are given , to find ...
... answers to the product , and the divisor and quotient to the factors , of multiplication . In multiplication , two factors are given , to find their product ; and in division , one of two factors and their product are given , to find ...
Σελίδα 46
... answer required In this illustration , to render the explanation the more concise , the naming of the denominations of the figures has been omitted . When , as in the operation preceding the last , results only are written down , the ...
... answer required In this illustration , to render the explanation the more concise , the naming of the denominations of the figures has been omitted . When , as in the operation preceding the last , results only are written down , the ...
Σελίδα 52
... answer required , 5 years . Hence , when the divisor contains one or more ciphers at the right , we may , to perform the division , 5 , 164 . Cut off the ciphers from the right of the divisor , and the same number of figures from the ...
... answer required , 5 years . Hence , when the divisor contains one or more ciphers at the right , we may , to perform the division , 5 , 164 . Cut off the ciphers from the right of the divisor , and the same number of figures from the ...
Σελίδα 56
... answer required . In the second operation , we add in the multiplicand taken as the product by the 1 ten of the multiplier , as we multiply by the 4 units ; thus , 6 X 4 = 24 , of which we write down the 4 and carry the 2 . 2 X 4 = 8 ...
... answer required . In the second operation , we add in the multiplicand taken as the product by the 1 ten of the multiplier , as we multiply by the 4 units ; thus , 6 X 4 = 24 , of which we write down the 4 and carry the 2 . 2 X 4 = 8 ...
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12 per cent acres amount annexed annuity Arithmetic arithmetical series balance barrels becomes due bill bought bushels carats ciphers column common difference common fraction compound interest compound numbers contain continued fraction cords cost cube root cubic diameter Divide dividend division dollars equal EXAMPLES exchange expressed decimally figures gain gallons given number given rate grain greatest common divisor Hence hogshead hundred inches indorser last term least common multiple less longitude lowest terms miles minuend mixed number months multiplicand Multiply NOTE number denoting number of days number of terms obtain paid par value payable payment pound sterling pounds premium present worth prime factors principal proportion quantity quotient rate per cent ratio received Reduce remainder repetend RULE SECOND OPERATION shillings side sold square root subtract tens third thousand tons trial divisor true divisor weight whole numbers wine write yards