The National Arithmetic on the Inductive System: Combining the Analytic and Synthetic Methods : Forming a Complete Course of Higher ArithmeticRobert S. Davis & Company, 1878 - 450 σελίδες |
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Σελίδα 37
... cost of 4 books at 9 dollars each , we cannot multiply books and dollars together , which would be absurd , but we can , by regarding the 4 as an abstract number , take the 9 dollars , or cost of 1 book 4 times , and the product , 36 ...
... cost of 4 books at 9 dollars each , we cannot multiply books and dollars together , which would be absurd , but we can , by regarding the 4 as an abstract number , take the 9 dollars , or cost of 1 book 4 times , and the product , 36 ...
Σελίδα 40
... cost at 73 dollars per acre ? Ans . $ 26645 . 18. What will 97 tons of iron cost at 57 dollars a ton ? Ans . $ 5529 . 19. What will 397 yards of cloth cost at 7 dollars per yard ? Ans . $ 2779 . 20. What will 569 hogsheads of molasses cost ...
... cost at 73 dollars per acre ? Ans . $ 26645 . 18. What will 97 tons of iron cost at 57 dollars a ton ? Ans . $ 5529 . 19. What will 397 yards of cloth cost at 7 dollars per yard ? Ans . $ 2779 . 20. What will 569 hogsheads of molasses cost ...
Σελίδα 42
... cost 35 acres of land at 316 dollars an acre ? OPERATION . 316 dollars , cost of 1 acre . 7 2212 dollars , cost of 7 acres . 5 Ans . 11060 dollars . The factors of 35 are 7 and 5. Now , if we multiply the price of one acre by 7 , we get the ...
... cost 35 acres of land at 316 dollars an acre ? OPERATION . 316 dollars , cost of 1 acre . 7 2212 dollars , cost of 7 acres . 5 Ans . 11060 dollars . The factors of 35 are 7 and 5. Now , if we multiply the price of one acre by 7 , we get the ...
Σελίδα 43
... cost at 40 dollars per bale ? Ans . 28000 dollars . OPERATION . Multiplicand Multiplier Product 700 40 28000 The multiplicand we resolve into the factors 7 and 100 , and the multiplier into the factors 4 and 10. Now , it is evident ...
... cost at 40 dollars per bale ? Ans . 28000 dollars . OPERATION . Multiplicand Multiplier Product 700 40 28000 The multiplicand we resolve into the factors 7 and 100 , and the multiplier into the factors 4 and 10. Now , it is evident ...
Σελίδα 45
... cost of 1 pen- cil , when 4 pencils cost 24 cents , we separate or divide the 24 cents into 4 equal parts , of which one part is 6 cents . Hence , 1 pencil costs 6 cents , when 4 pencils cost 24 cents . 71. The remainder will always be ...
... cost of 1 pen- cil , when 4 pencils cost 24 cents , we separate or divide the 24 cents into 4 equal parts , of which one part is 6 cents . Hence , 1 pencil costs 6 cents , when 4 pencils cost 24 cents . 71. The remainder will always be ...
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12 per cent acres amount annexed annuity Arithmetic arithmetical series balance barrels becomes due bill bought bushels carats ciphers column common difference common fraction compound interest compound numbers contain continued fraction cords cost cube root cubic diameter Divide dividend division dollars equal EXAMPLES exchange expressed decimally figures gain gallons given number given rate grain greatest common divisor Hence hogshead hundred inches indorser last term least common multiple less longitude lowest terms miles minuend mixed number months multiplicand Multiply NOTE number denoting number of days number of terms obtain paid par value payable payment pound sterling pounds premium present worth prime factors principal proportion quantity quotient rate per cent ratio received Reduce remainder repetend RULE SECOND OPERATION shillings side sold square root subtract tens third thousand tons trial divisor true divisor weight whole numbers wine write yards