 | Robert Simson - 1762 - 488 σελίδες
...parallelograms, &c. Q^ED PROP. XXXVII. THEOR. HPRi ANGLEs upo'n the fame bafe, and between the fame parallels, are equal to one another. Let the triangles ABC, DBC be upon the fairie bafe BC and between the fame parallels AD; BC . the triangle ABC is equal to the triangle DBC.... | |
 | 1867 - 964 σελίδες
...to show. The reader will remember that in Problem XXIV (page 308) it was shown that triangles on the same base and between the same parallels are equal to one another, and that triangles on equal bases and between the same parallels are also equal to one another. Now... | |
 | Robert Simson - 1775 - 534 σελίδες
...EFGH. Wherefore parallelograms, &c. Q^ED PROP. XXXVII. THEOR.. upon the fame bafe, and between the fame parallels, are equal' to one another. Let the triangles ABC, DBC be upon the fame bafe BC and between the fame parallels -rx A Tl AD, BC: The triangle ABC *i. AA* is equal to the... | |
 | Alexander Ingram - 1799 - 374 σελίδες
...PROP. B BooK I. PROP. XXXVII. THEOR. See M. rripviANGLES upon the fame bafe, and between the JL fame parallels, are equal to one another. Let the triangles ABC, DBC be upon the fame bafe BC, and between the fame parallels AD, BC : The triangle ABC is equal to the triangle DBC.... | |
 | Robert Simson - 1804 - 528 σελίδες
...parallelograms, &c. Q^ED »• 34. T PROP. XXXVII. THEOR. RIANGLES upon the fame bafe, and between the fame parallels, are equal to one another, Let the triangles ABC, DBC be upon the fame bafe BC and between the fame parallelspi A Tl Ti* AD, BC. the triangle ABC iaF4 A AJ -C equal... | |
 | Robert Simson - 1806 - 548 σελίδες
...divides the paralkio c 4. 1. gram ACDB into two equal parts. QED PROP. XXXV. THEOR. See N. PARALLELOGRAMS upon the same base, and between the same parallels, are equal to one another. Sue OH- Let the parallelograms ABCD, EBCF be upon the same base 2dand3d BC, and between the same parallels... | |
 | Euclid - 1810 - 554 σελίδες
...same EBCH : therefore also the parallelogram ABCD is equal to EFGH. Wherefore, parallelograms, &c. QED PROP. XXXVII. THEOR. TRIANGLES upon the same base,...the triangles ABC, DBC be upon the same base BC, and ketween the same parallels p » , AD, BC : the triangle ABC B equal to the triangle DBC. Produce AD... | |
 | John Mason Good - 1813 - 714 σελίδες
...diameter bisects them, that is, divides them in two equal parts. Prop. XXXV. Theor. Parallelograms upon the same base and between the same parallels, are equal to one another. Prop. XXXVI. Theor. Parallelograms upon equal basis, and between the same parallels, are equal to one... | |
 | Euclides - 1814 - 560 σελίδες
...same EBCH : Therefore also the parallelogram ABCD is equal to EFGH. Wherefore parallelograms,"&c. QED PROP. XXXVII. THEOR. TRIANGLES upon the same base,...DBC, be upon the same base BC, and between the same r' parallels AD, BC : The triangle ABC is equal to the triangle DBC. through B draw3 BE pa- ^ ^ Produce... | |
 | Euclides - 1816 - 592 σελίδες
...i divides the parallelogram ACDB into two equal" parts. PROP. XXXV. THEOR. , s«eN. PARALLELOGRAMS upon the same base, and between the same parallels, are equal to one another. See the ad Let the parallelograms ABCD, EBCF be upon the same and 3d fi. base BC, and between the same... | |
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Parallelograms upon the same base and between the same parallels, are equal to one another. 
