Mathematics for Common Schools: A Manual for Teachings, Including Definitions, Principles, and Rules and Solutions of the More Difficult ProblemsD.C. Heath & Company, 1895 - 312 σελίδες |
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Σελίδα 76
... rods mentally and 24 rods deducted from the sum , only the answer being written . 779. In dividing 5 bu . by 4 , 79 , the answer is not to be given as 14 bu .; the division should be continued through pecks . The result in 88 should ...
... rods mentally and 24 rods deducted from the sum , only the answer being written . 779. In dividing 5 bu . by 4 , 79 , the answer is not to be given as 14 bu .; the division should be continued through pecks . The result in 88 should ...
Σελίδα 81
... rods in a square mile , 320 × 320 , and divide by the number of square rods in an acre , 160 . 14. The number of yards = ( 5 + 3 + 4 + 7 + 3 + 6 + 12 + 10 ) X 51 15. Original dimensions 12 rods × 13 rods , making area 156 sq . rd ...
... rods in a square mile , 320 × 320 , and divide by the number of square rods in an acre , 160 . 14. The number of yards = ( 5 + 3 + 4 + 7 + 3 + 6 + 12 + 10 ) X 51 15. Original dimensions 12 rods × 13 rods , making area 156 sq . rd ...
Σελίδα 104
... rods x 80 rods . 16. 9543951295x45x4 . 17. 4000 ÷ 2 . 19. 3 T. will cost $ 15 ; 480 lb. @ ± ¢ per lb. will cost $ 1.20 ; total , $ 16.20 . 20. For $ 10 , I can buy 2 tons ; for 80 , I can buy ( 80 × 4 ) lb. , or 320 lb. 23. 347495 ...
... rods x 80 rods . 16. 9543951295x45x4 . 17. 4000 ÷ 2 . 19. 3 T. will cost $ 15 ; 480 lb. @ ± ¢ per lb. will cost $ 1.20 ; total , $ 16.20 . 20. For $ 10 , I can buy 2 tons ; for 80 , I can buy ( 80 × 4 ) lb. , or 320 lb. 23. 347495 ...
Σελίδα 132
... rods = ( 1600 + 146 ) ÷ 18 . = 21. Let 10x represent cost , then loss = x ; and selling price = 9x = $ 117 ; x = 13 ; cost $ 130 . A gain of 10 % would be $ 13 , making the price at which he should have sold it to gain $ 130 + $ 13 ...
... rods = ( 1600 + 146 ) ÷ 18 . = 21. Let 10x represent cost , then loss = x ; and selling price = 9x = $ 117 ; x = 13 ; cost $ 130 . A gain of 10 % would be $ 13 , making the price at which he should have sold it to gain $ 130 + $ 13 ...
Σελίδα 157
... rods by multiplying by 40 , obtaining 16.656 rd .; .656 rd . = 3.608 yd .; etc .; etc. = 6. See Art . 986 , 7. That selling price , $ 3.54 , must be in- creased , or $ .59 , to gain 163 % . $ 3.54 + $ .59 $ 4.13 . Ans . 240 x 38 x 9 7 ...
... rods by multiplying by 40 , obtaining 16.656 rd .; .656 rd . = 3.608 yd .; etc .; etc. = 6. See Art . 986 , 7. That selling price , $ 3.54 , must be in- creased , or $ .59 , to gain 163 % . $ 3.54 + $ .59 $ 4.13 . Ans . 240 x 38 x 9 7 ...
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acres algebraic altitude amount angle answer apothem Arithmetic base bisecting calculate Cancel cents chord ciphers circle circumference common fraction construct contains convex surface cost days of grace deducting diameter difference discount dividend dividing division draft draw drawn employed equal equation examples exercises factors figure frustum given gives greatest common divisor Heart of Oak hypotenuse improper fraction inches interest intersecting least common multiple length measure method minuend mixed numbers multiplying NOTES ON CHAPTER number of degrees number of square obtain par value payment perpendicular pounds principal problems profits protractor pupils quarts quotient radius rectangle reduce remaining result rhombus right-angled triangle rods RULE scholars selling price side slant height solve subtract subtrahend teacher whole number write yards