 | Charles Butler - 1814 - 540 σελίδες
...dividend will have as many decimal places as there are in the divisor and quotient together ; wherefore the quotient must contain as many decimal places as the number of decimals in the dividend exceeds that in the divisor ; which was to be shewn. 3. Divide 17.0146 by... | |
 | Charles Davies, William Guy Peck - 1855 - 628 σελίδες
...any desirable extent, or till a remainder is found equal to 0 ; then point ofi" from the right hand as many decimal places as the number of decimal places in the dividend exceeds that in the divisor ; if there are not so many in the quotient, prefix O's till the requisite... | |
 | Horatio Nelson Robinson - 1860 - 444 σελίδες
...denominator of the divisor. Therefore, II. The quotient of one number divided by another in the decimal form must contain as many decimal places as the number -of decimal places in the dividend exceed the number in the divisor. 1. Divide 34.368 by 5.37. OPER vriosr ANALYSIS. We first divide as... | |
 | Emerson Elbridge White - 1873 - 260 σελίδες
...The dividend contains as many decimal places as both divisor and quotient. 2. The quotient contains as many decimal places as the number of decimal places in the dividend exceeds the number in the divisor. 3. Each removal of the decimal point one place to the left, divides... | |
 | Daniel W. Fish - 1874 - 542 σελίδες
...the divisor and quotient, it contains as many decimal places as both divisor and quotient. Hence, 3. The quotient must contain as many decimal places as the number of decimal places in the dividend exceeds those in the divisor.\ WRITTEN MXERCISE8, 296. 1. Divide .952 by .7. OPKEATION. ANALYSIS. —... | |
 | Horatio Nelson Robinson - 1875 - 462 σελίδες
...denominator of the divisor. Therefore, II. The quotient of one number divided by another in the decimal form must contain as many decimal places as the number of' decimal places in the dividend exceed the number in the divisor. 1. Divide 34.368 by 5.37. OPERATION ANALYSIS. We first divide as... | |
 | William James Milne - 1877 - 402 σελίδες
...quotient, how many decimal places will there be in the quotient? 215. PRINCIPLE. — The quotient will contain as many decimal places as the number of decimal places in the dividend exceeds those in the divisor. WRITTEN EXERCISES. 1. Divide 8.88 by 2.4. PROCESS. ANALYSIS.— 8.88... | |
 | Samuel Mecutchen - 1877 - 128 σελίδες
...in the quotient. From these operations we derive this principle : — In any quotient there will be as many decimal places as the number of decimal places in the dividend exceeds the number in the divisor, WRITTEN EXERCISES. 1. Divide 14.688 by 12. 2. Divide 146.88 by 1.2.... | |
 | Joseph Ray - 1880 - 420 σελίδες
...decimal places as the divisor ; and wJien botii have the same mimber, tfie quotient is an integer. 2. The quotient must contain as many decimal places as the number of those in the dividend exceeds the number of those in tJie divisor. PROBLEM. — Divide .50312 by .19... | |
 | William James Milne - 1882 - 224 σελίδες
...quotient, how many decimal places will there be in the quotient? 210. PRINCIPLE. — The quotient iintt contain as many decimal places as the number of decimal places in the dividend exceeds those in the divisor. WRITTEN EXERCISES. « 211. 1. Divide .07245 by .23. PROCESS. ANALYSIS.... | |
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... as many decimal places as the number of decimal places in the dividend exceeds those in the divisor, prefixing ciphers to the quotient, if necessary. 
