Modern Methods in Elementary GeometryMacmillan, 1868 - 112 σελίδες |
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Σελίδα 19
... ABCD be a parallelogram . Then shall AB = CD , BC = DA , A B A = C , and B = D . Join BD . D Then the alternate angle ABD = the alternate angle CDB , [ 1. 8. Cor . 2 . and the alternate angle BDA = the alternate angle DBC . Therefore in ...
... ABCD be a parallelogram . Then shall AB = CD , BC = DA , A B A = C , and B = D . Join BD . D Then the alternate angle ABD = the alternate angle CDB , [ 1. 8. Cor . 2 . and the alternate angle BDA = the alternate angle DBC . Therefore in ...
Σελίδα 28
... ABCD is a parallelogram . E , F the middle points of AB , CD . Shew that BF , DE trisect the diagonal AC . 26. A pavement is to be formed of tiles of the same regular figure . Shew that the only figures which can be used are the ...
... ABCD is a parallelogram . E , F the middle points of AB , CD . Shew that BF , DE trisect the diagonal AC . 26. A pavement is to be formed of tiles of the same regular figure . Shew that the only figures which can be used are the ...
Σελίδα 44
... A B C D Let O and I be equal circles , and let the arc AB be equal to the arc CD . AOB = CID , Then shall and 0 the chord AB = the chord CD . Apply the circle O to the circle I so that the point O may be on I. The circumferences will ...
... A B C D Let O and I be equal circles , and let the arc AB be equal to the arc CD . AOB = CID , Then shall and 0 the chord AB = the chord CD . Apply the circle O to the circle I so that the point O may be on I. The circumferences will ...
Σελίδα 60
... ABCD is bisected by its diagonal . For the triangles ABD , BDC have been shewn to be con- gruent ( 1. 16 ) , and are therefore equal H D B B K COR . The complements about the diameter , that is , the figures AK , KC are equal . also For ...
... ABCD is bisected by its diagonal . For the triangles ABD , BDC have been shewn to be con- gruent ( 1. 16 ) , and are therefore equal H D B B K COR . The complements about the diameter , that is , the figures AK , KC are equal . also For ...
Σελίδα 61
... ABCD . Again , from the whole fig . ABCF take away the tri- angle EAB . There is left the parallelogram EBCF . Therefore the parallelogram ABCD = the parallelogram EBCF . COR . Parallelograms upon equal bases and between the same ...
... ABCD . Again , from the whole fig . ABCF take away the tri- angle EAB . There is left the parallelogram EBCF . Therefore the parallelogram ABCD = the parallelogram EBCF . COR . Parallelograms upon equal bases and between the same ...
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Algebra alternate angle altitude ARITHMETIC base BC² BEGINNERS bisect BROOKE FOSS WESTCOTT Cambridge centre chord Christ's College circle touching circumference Clifton College cloth coincide congruent CONIC SECTIONS construct contains convex angle Crown 8vo describe a circle diagonals diameter dicular distance divide Edward Thring ELEMENTARY TREATISE equal angles equally distant equiangular equilateral triangle Examination Papers Exercises exterior angle Fcap Fellow of St GEOMETRY given circle given line given point given square given straight line greater Greek Text Head Master Hence inscribe intersect John's College Join JOSEPH WOLSTENHOLME Jugurtha late Fellow Latin Let ABCD line drawn locus Mathematical Lecturer measure meet middle point MIXED MATHEMATICS numerous parallel to BC parallelogram perpen perpendicular polygon problems quadrilateral figure radius rectangle right angles Second Edition Shew similar triangles student tangent THEOREM VII Third Edition trapezium triangle ABC vertex
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