Modern Methods in Elementary GeometryMacmillan, 1868 - 112 σελίδες |
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Αποτελέσματα 1 - 5 από τα 41.
Σελίδα 8
... PARALLELS . A BE D FGC Parallel straight lines are such as being produced ever so far both ways do not meet . If a straight line EF cut the two straight lines AB , CD , it makes with either of them four angles which we will denote by ...
... PARALLELS . A BE D FGC Parallel straight lines are such as being produced ever so far both ways do not meet . If a straight line EF cut the two straight lines AB , CD , it makes with either of them four angles which we will denote by ...
Σελίδα 9
... parallel to CD . COR . 2. If the alternate angle AGH is equal to the alternate angle GHD , AB is parallel to CD . : For AGH = EGB , COR . 3. If the two interior angles BGH , THE STRAIGHT LINE , 9.
... parallel to CD . COR . 2. If the alternate angle AGH is equal to the alternate angle GHD , AB is parallel to CD . : For AGH = EGB , COR . 3. If the two interior angles BGH , THE STRAIGHT LINE , 9.
Σελίδα 10
... parallel to CD . For BGH + GHD will then be equal to BGH + EGB , and therefore EGB = GHD . THEOREM VIII . If AB be parallel to CD , then shall the angle EGB be E I A- -B -M H D с ! equal to the angle GHD . For if not let EGM be equal to ...
... parallel to CD . For BGH + GHD will then be equal to BGH + EGB , and therefore EGB = GHD . THEOREM VIII . If AB be parallel to CD , then shall the angle EGB be E I A- -B -M H D с ! equal to the angle GHD . For if not let EGM be equal to ...
Σελίδα 11
... parallel to one another . E Draw EFHG cutting AB , KL , and CD , in F , H , and G. F A B H Then = EFB FHL . K L G And = FHL HGD . C-- D Therefore EFB = HGD . Therefore AB is parallel to CD . I. 7 . TRIANGLES . THEOREM X. If one side BC ...
... parallel to one another . E Draw EFHG cutting AB , KL , and CD , in F , H , and G. F A B H Then = EFB FHL . K L G And = FHL HGD . C-- D Therefore EFB = HGD . Therefore AB is parallel to CD . I. 7 . TRIANGLES . THEOREM X. If one side BC ...
Σελίδα 19
... parallel . THEOREM XVI . The opposite sides and angles of parallelograms are equal . Let ABCD be a parallelogram . Then shall AB = CD , BC = DA , A B A = C , and B = D . Join BD . D Then the alternate angle ABD = the alternate angle CDB ...
... parallel . THEOREM XVI . The opposite sides and angles of parallelograms are equal . Let ABCD be a parallelogram . Then shall AB = CD , BC = DA , A B A = C , and B = D . Join BD . D Then the alternate angle ABD = the alternate angle CDB ...
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Algebra alternate angle altitude ARITHMETIC base BC² BEGINNERS bisect BROOKE FOSS WESTCOTT Cambridge centre chord Christ's College circle touching circumference Clifton College cloth coincide congruent CONIC SECTIONS construct contains convex angle Crown 8vo describe a circle diagonals diameter dicular distance divide Edward Thring ELEMENTARY TREATISE equal angles equally distant equiangular equilateral triangle Examination Papers Exercises exterior angle Fcap Fellow of St GEOMETRY given circle given line given point given square given straight line greater Greek Text Head Master Hence inscribe intersect John's College Join JOSEPH WOLSTENHOLME Jugurtha late Fellow Latin Let ABCD line drawn locus Mathematical Lecturer measure meet middle point MIXED MATHEMATICS numerous parallel to BC parallelogram perpen perpendicular polygon problems quadrilateral figure radius rectangle right angles Second Edition Shew similar triangles student tangent THEOREM VII Third Edition trapezium triangle ABC vertex
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