Plane and Solid GeometryCharles E. Merrill Company, 1911 - 546 σελίδες |
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Αποτελέσματα 1 - 5 από τα 73.
Σελίδα 40
... bisect LABC . Then , in the △ ABD and DBC , Also And AB = BC . BD = BD , LABDL CBD . ... A △ ABD = △ CBD , ( two are equal if two sides and the included △ tively , to two sides and the included Hyp . Ident . Constr . Art . 96 . of ...
... bisect LABC . Then , in the △ ABD and DBC , Also And AB = BC . BD = BD , LABDL CBD . ... A △ ABD = △ CBD , ( two are equal if two sides and the included △ tively , to two sides and the included Hyp . Ident . Constr . Art . 96 . of ...
Σελίδα 42
... bisects the vertex angles , and also bisects the base at right angles . Ex . 2. Hence , at any point in a given straight line , construct exactly by use of ruler and compasses a perpendicular to that line . Ax . 1 . Q. E. D. PROPOSITION ...
... bisects the vertex angles , and also bisects the base at right angles . Ex . 2. Hence , at any point in a given straight line , construct exactly by use of ruler and compasses a perpendicular to that line . Ax . 1 . Q. E. D. PROPOSITION ...
Σελίδα 43
... bisect any given straight line . Ex . 2. Bisect any given angle 40B , Ax . 1 . Q. E. D. B PROPOSITION XIII . THEOREM 103. An exterior angle of a TRIANGLES 43.
... bisect any given straight line . Ex . 2. Bisect any given angle 40B , Ax . 1 . Q. E. D. B PROPOSITION XIII . THEOREM 103. An exterior angle of a TRIANGLES 43.
Σελίδα 47
... bisect the FBC and meet the line AC at H. Draw FH . Then , in the AFBH and BHC , F " B = BC , Hyp . BH = BH , LFBH = / CBH . : . Δ ΓΒΗ = Δ ΒΗΟ . FBH Ident . Constr . ( Why ? ) But : . F'H = CH , ( homologous sides of equal A ) . AH + HF ...
... bisect the FBC and meet the line AC at H. Draw FH . Then , in the AFBH and BHC , F " B = BC , Hyp . BH = BH , LFBH = / CBH . : . Δ ΓΒΗ = Δ ΒΗΟ . FBH Ident . Constr . ( Why ? ) But : . F'H = CH , ( homologous sides of equal A ) . AH + HF ...
Σελίδα 71
Fletcher Durell. PROPOSITION XXXVI . THEOREM 161. The diagonals of a parallelogram bisect each other . B A D Given the diagonals AC and BD of the ABCD , intersecting at F. To prove AF FC , and BF = FD . Proof . Let the pupil supply the ...
Fletcher Durell. PROPOSITION XXXVI . THEOREM 161. The diagonals of a parallelogram bisect each other . B A D Given the diagonals AC and BD of the ABCD , intersecting at F. To prove AF FC , and BF = FD . Proof . Let the pupil supply the ...
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Συχνά εμφανιζόμενοι όροι και φράσεις
ABCD altitude base bisector bisects chord circumference circumscribed coincide cone of revolution denoted diagonal diameter dihedral angle divided equidistant equilateral triangle equivalent exterior angle figure Find the area Find the radius frustum geometric given circle given line given point Hence homologous sides hypotenuse intersect isosceles trapezoid isosceles triangle lateral area lateral edges Let the pupil line drawn measure midpoints number of sides opposite parallel lines parallelogram parallelopiped pass a plane perimeter perpendicular plane MN plane parallel polyhedron prism prismatoid produced proportional pyramid Q. E. D. Ex Q. E. D. PROPOSITION quadrilateral radii ratio rectangle regular polygon rhombus right angles right triangle secant segments similar slant height sphere spherical polygon spherical triangle square pyramid surface symmetrical tangent tetrahedron THEOREM trapezoid triangle ABC trihedral vertex vertices
Δημοφιλή αποσπάσματα
Σελίδα 241 - If two triangles have an angle of one equal to an angle of the other, and...
Σελίδα 103 - A chord is a straight line joining the extremities of an arc.
Σελίδα 54 - Every point in the bisector of an angle is equidistant from the sides of the angle. Hyp. Z DAB = Z DAC and 0 is any point in AD. To prove 0 is equidistant from AB and AC. Draw OP _L AB and OP' _L AC, and prove the equality of the two triangles.
Σελίδα 82 - The perpendiculars from the vertices of a triangle to the opposite sides meet in a point.
Σελίδα 114 - In the same circle or in equal circles, if two chords are unequal, they are unequally distant from the center, and the greater chord is at the less distance.
Σελίδα 47 - If two triangles have two sides of one equal respectively to two sides of the other...
Σελίδα 416 - Every section of a circular cone made by a plane parallel to the base is a circle. Let the section abcd of the circular cone S-ABCD be parallel to the base. To prove that abcd is a circle.
Σελίδα 35 - The perpendicular is the shortest straight line that can be drawn from a given point to a given straight line...
Σελίδα 193 - ... they have an angle of one equal to an angle of the other and the including sides are proportional; (c) their sides are respectively proportional.
Σελίδα 450 - If two angles of a spherical triangle are equal, the sides opposite these angles are equal and the triangle is isosceles. Given the spherical triangle ABC, with angle B equal to angle C. To prove that AC = AB. Proof. Let A A'B'C ' be the polar triangle of A ABC.