Elements of Geometry |
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Αποτελέσματα 1 - 5 από τα 32.
Σελίδα 73
A Radius of a circle is any straight line drawn from the centre to the circumference
, as 0 A , Fig . 1 . 163 . DEF . A Diameter ... Hence , all its diameters are equal ,
since the diameter is equal to twice the radius . o A A P . D Fig . 1 . Fig . 2 . Fig . 3 .
A Radius of a circle is any straight line drawn from the centre to the circumference
, as 0 A , Fig . 1 . 163 . DEF . A Diameter ... Hence , all its diameters are equal ,
since the diameter is equal to twice the radius . o A A P . D Fig . 1 . Fig . 2 . Fig . 3 .
Σελίδα 78
In the equal circles ABP and A ' B ' P ' let arc RS = arc R ' S ' . We are to prove
ZROS = R ' O ' S ' . Apply O A B P to O A ' B ' P ' , so that the radius 0 R shall fall
upon OʻR ' . Then S , the extremity of arc RS , will fall upon S ' , the extremity of
arc ...
In the equal circles ABP and A ' B ' P ' let arc RS = arc R ' S ' . We are to prove
ZROS = R ' O ' S ' . Apply O A B P to O A ' B ' P ' , so that the radius 0 R shall fall
upon OʻR ' . Then S , the extremity of arc RS , will fall upon S ' , the extremity of
arc ...
Σελίδα 80
CONVERSELY : In the same circle , or equal circles , equal chords subtend equal
arcs . PI In the equal circles ABP and A ' B ' P ' , let chord RS = chord RS . We are
to prove arc R S = arc ... The radius perpendicular . . arc R S = arc R ' S ' , ( in ...
CONVERSELY : In the same circle , or equal circles , equal chords subtend equal
arcs . PI In the equal circles ABP and A ' B ' P ' , let chord RS = chord RS . We are
to prove arc R S = arc ... The radius perpendicular . . arc R S = arc R ' S ' , ( in ...
Σελίδα 81
... and let the radius C S be perpendicular to A B at the point M . We are to prove
AM = BM , and arc A S = arc B S . Draw C A and C B . CA = CB , ( being radii of
the same 0 ) ; . : . A AC B is isosceles , § 84 ( the opposite sides being equal ) ; .
... and let the radius C S be perpendicular to A B at the point M . We are to prove
AM = BM , and arc A S = arc B S . Draw C A and C B . CA = CB , ( being radii of
the same 0 ) ; . : . A AC B is isosceles , § 84 ( the opposite sides being equal ) ; .
Σελίδα 103
Let A and B be the two known points ; n the distance of the required point from A ,
o its distance from B . It is required to find a point at the given distances from A
and B . From A as a centre , with a radius equal to n , describe an arc . From B as
...
Let A and B be the two known points ; n the distance of the required point from A ,
o its distance from B . It is required to find a point at the given distances from A
and B . From A as a centre , with a radius equal to n , describe an arc . From B as
...
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Συχνά εμφανιζόμενοι όροι και φράσεις
acute adjacent altitude arc A B base bisect called centre chord circle circumference circumscribed coincide common Cons construct contained COROLLARY describe diagonals diameter difference direction divided Draw equal distances equal respectively equilateral equivalent erected extremities fall figure formed four given given line greater homologous sides hypotenuse included inscribed intersect isosceles joining less Let A B limit line A B lines drawn mean measured meet middle point multiplied one-half opposite sides parallelogram perimeter perpendicular plane position PROBLEM proportional prove Q. E. D. PROPOSITION quantities radii radius equal ratio rect rectangles regular polygon right angles segment shortest Show similar similar polygons square straight line Substitute subtend surface symmetrical tangent THEOREM triangle variable vertex vertices
Δημοφιλή αποσπάσματα
Σελίδα 30 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz.
Σελίδα 116 - To describe an isosceles triangle having each of the angles at the base double of the third angle.
Σελίδα 126 - The first of four magnitudes is said to have the same ratio to the second which the third has to the fourth, when...
Σελίδα 197 - Construct a rectangle having the difference of its base and altitude equal to a given line, and its area equivalent to the sum of a given triangle and a given pentagon.
Σελίδα 192 - In any proportion, the product of the means is equal to the product of the extremes.
Σελίδα 132 - If a line divides two sides of a triangle proportionally, it is parallel to the third side.
Σελίδα 165 - Any two rectangles are to each other as the products of their bases by their altitudes.
Σελίδα 62 - Every point in the bisector of an angle is equally distant from the sides of the angle ; and every point not in the bisector, but within the angle, is unequally distant from the sides of the angle.
Σελίδα 63 - A CIRCLE is a plane figure bounded by a curved line, all the points of which are equally distant from a point within called the centre; as the figure ADB E.
Σελίδα 136 - The areas of two triangles which have an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles. A D A' Hyp. In triangles ABC and A'B'C', To prove AABC A A'B'C' A'B' x A'C ' Proof. Draw the altitudes BD and B'D'.