per cent. above par, that is, every 100 dollars worth $115; I demand what 3 shares are worth at 400 dollars each? Root, p. 67. Answer, 1380 dollars. 27. Sold a vessel for 2500 dollars, and I owned; what was my part of the money? Ans. $781 25 cts. Root, p. 68. 28. A merchant in Connecticut paid a merchant in England, £4349 16s. 4d. in dollars at 4s. 6d. each; how much was that value in New-England currency of 6s. to the dollar? Ans. £5799 15s. 1d. Root, p. 68. 29. A gentleman sent a ship on a whaling voyage, and agreed to divide the proceeds of the voyage into 60 shares and give the captain 4; the ship afterwards returned with a cargo worth ten thousand dollars-I demand the captain's part? Ans. $666 66 cts. Root, p. 68. 30. A bankrupt owes £1490 5s. 10d. but the whole of his estate is worth no more than £931 8s. 74d.—I demand how much he can pay his creditors on the pound? Ans. 12s. 6d. Root, p. 68. 31. What is the price of a ship when of her are worth $17654? Ans. $2824 40 cts. 8 N. B. As are to 1765.25 :: so are 32. Suppose you have 476 dollars 37 Root, p. 68. to 2824.40. cents of deferred stock, and every dollar is worth 65 cents; how much is the whole worth? Ans. $309 64 cts. Root, p. 68. 33. If 7 buttons cost 24d., what for a great gross, or 1728? Ans. £2 11s. 54d. 34. Suppose a legislature of a state grant a tax of 14d. on the pound; how much must a man pay who is rated £134 16s. 8d. on the list? Ans. 16s. 10d. Root, p. 69. See Part 9, p. 273. 240d. 6q. 1d. : .025q. common multiplier. 35. Harry had pears, 9 of which were worth 6d., Billy had apples, 8 of which were worth 2d.—I demand what number of apples Billy must give Harry for 15 of his pears? Root, p. 69. Ans. 40. 1st. as 9 P.: 6d. :: 15 P.: 10d. 36. A can do a job of work in 10 days, B.can do the same in 15 days; how long will it take both together to do the same work? Ans. 6 days. A 10 days. B 15 Make 252 = 12.5 that is, at the rate of 12 days for one man.' Then, As 1 man is to 12.5 days: 2 men : 6.25 days inversely. 37. If 100 dollars gain 6 dollars in 12 months, what principle will give the same in 5 months? Ans. $240. Root, p. 70. As 12 mo. : $100 :: 5 mo.: 240 inversely. 38. What will be the price of 72 yards of cambrick, of which 9 yards cost £5 12s.? Ans. £44 16s. Multiply the second term by 8, the product will be the answer; because any number multiplied by 8, will produce the same result as if it were multiplied by 72, and that product divided by 9. 39. What will 9 yards of cambrick cost at the rate of £44 16s. for 72 yards? Ans. £5 12s. Hutton, p. 38. Divide the second term by 8, the quotient will be the answer. 72 yds. £44 16s. 9 yds. : £5 12s. 40. How many men must be employed to finish a piece of work in 15 days, which 5 men can do in 24 days? Ans. 8 men. Hutton, p. 38. Examine Mr. Hutton's Arithmetic, page 36. 41. A garrison being besieged, has 5 months' provision in it, at the rate of 12 ounces a day for each man; but being informed that it cannot be relieved till after 9 months, how much per day must each man have that the provisions may last that time? Ans. 6 oz. Hutton, p. 39. 42. What will the tax be on £763 15s., at the rate of 3s. 6d. per pound? Ans. £133 138. 14d. Hutton, p. 39. 43. What will 7 cwt. 1 qr. of sugar cost, at the rate of 43 cwt, 2 qrs. for £159 2s.? 44. A person stopping payment, Ans. £26 10s. 4d. Hutton, p. 39. owes to several £977, but compounds with them for 8s. 74d. per pound; what must he pay them in all? Ans. £420 6s. 31d. 45. What must be given for 7 cwt. 3 qrs. 14 lb. cheese, at £1 14s. 2d. per cwt.? Ans. £13 9s. 03d. 46. If the tax on £763 15s. be £133 rate is it per pound? Ans. 3s. 6d. Hutton, p. 39. 13s. 1d., at what Hulton, p. 48. 47. What will the transportation of 8 cwt. 3 qrs. 7 lb. cost, at the rate of 10d. per stone of 14 lb. ? Ans. £2 18s. 9d. Hutton, p. 40. 48. What must be paid for 73 pieces of lead, each weighing 1 cwt. 3 qrs. 7 lb., at £10 4s. per fother of 194 cwt.? Ans. £69 48. 2d. 148q. Hutton, p. 40. 49. If 5 yards of cloth cost 14s. 2d., what must be given for 9 pieces containing each 21 yds. 1 qr.? Ans. £27 18. 101d. Hutton, p. 40. 50. A person, at the time of his outsetting in trade, owed £350; and had in cash £5307, in wares £713 Os. 7d., and in good debts £210 5s. 10d.: now, after having traded a year, he owed £703 17s., and had in cash £4874 9s. 4d., in bills £350, in wares £1075 14s. 34d., and in recoverable debts £613 13s. 104d.; what was his real gain that year? Ans. £329 4s. 1d. Hutton, p. 137. 51. If a hopper be 42 inches square on the top, and 24 inches deep, how much will it hold? Ans. 6.5625 bushels. Evans' Millwright and Miller's Guide, Chap. 2, p. 47. RULE. Multiply the length by the width at top, and that product by one third of the depth, divide the last product by 2150.4, if you calculate by inches, or by 1.24444 if work by feet; the quotient will be the contents in bushels you To make a Hopper to hold any given quantity, having the depth given. RULE. Divide the inches contained in the bushels it is to hold, by one third of the depth in inches; the quotient will be the square of one of the sides at top. that square for the length of one side. EXAMPLE. Extract the root of 52. The hopper shall hold 6.5625 bushels, the given depth is 24 inches, how long must be one side at top? Ans. 42 inches. OPERATION. Evans, p. 48. The number of bushels in the hopper, 6.5625 2150.4 262500 3281250 65625 131250 One third the depth 8)14112.00000 ✓1764.(42 Ans. in inches. 16 82). 164 OF A GARNER OR BIN. On the 5th of March, 1816, an old jockey bet that a bin 3.5 feet square and 3 feet high would hold 30 bushels; a young industrious man bet it would not hold so much: after calculating the contents, the jockey refused to pay the bet because he could pile on 30 bushels: pray how much did the bin hold without any prevarication? Answer, 29 bush. 16 qts. 7.9+ gills. One bushel = 1.24444 foot for a divisor. One side of the bin 3.5 feet x 3.5= 12.25 × 3 the height To make a Garner, Bin, or Box, that shall hold any given quantity, having two of its sides given, take the following RULE. Multiply the contents of one bushel by the number of bushels the bin is to hold, for a dividend; then multiply the given sides into each other for a divisor, the quotient will be the length of the side wanting. EXAMPLE. 53. Given, two sides of a garner 6.25 by 10.5 feet; required, the other side, to hold 184.6 bushels. Evans, p. 47. EXPLANATION. One side 6.25 x 10.5= 65.625 for a divisor; 1.24444 the eontents of a bushel x 184.6 the quantity in bushels = 229.723624 65.625 = 3.5 feet for the side required. 54. A distribution of £45 16s. is to be made between three persons in the following manner, viz: When the first has 40s. the second shall have 30s. and the third 10s.; what sum is each one's part in the whole? |