 | Robert Gibson - 1808 - 482 σελίδες
...the base AD, will be to the sum of the other sides, AB, BD, as the difference of those sides, is to the difference of the segments of the base, made by the perpendicular BE j viz. the difference between AE and ED. Jig. 12. Produce BD, till BG=AB the lesser leg ; and on... | |
 | Francis Nichols - 1811 - 162 σελίδες
...fall within the triangle, the base is to the sum of the other two sides, as their difference is to the difference of the segments of the base made by the perpendicular. Let ABC be the proposed triangle, C the vertex, AB the base, CD the perpendicular dividing the base... | |
 | Robert Gibson - 1818 - 502 σελίδες
...the base AD, will be to the sum of the other sides, AB, BD, as the difference of those sides, is to the difference of the segments of the base, made by the perpendicular BE ; ' Tiz. the difference between AE and ED. fig- 7%A.,*. Produce BD, till BG= AB the lesser leg ;... | |
 | Miles Bland - 1819 - 442 σελίδες
...given, the three first terms in the preceding proportion are given, and consequently the fourth, fe the difference of the segments of the base made by...be determined (76), and .-.the remaining angle at C (13). But if the perpendicular fall without the triangle, the fourth term in the proportion or sum... | |
 | Robert Gibson - 1832 - 290 σελίδες
...ABD, the base AD will be to the sum of the other sides AB, BD as the difference of those sides is to the difference of the segments of the base made by the perpendicular BE ; viz. the difference between AE and ED. Produce BD till BG=AB, the lesser leg ; and on B as a centre,... | |
 | James Thomson - 1844 - 328 σελίδες
...triangle =14=£A, the perpendicular = 12 =• p, and the sum of the sides = 28=* ; to find the sides. Ana. The difference of the segments of the base made by the perpendicular is 4, or, in general terms, 10. Given the base of a triangle = 14 = 2!). the perpendicular = 12 = p,... | |
 | James Thomson - 1845 - 328 σελίδες
...triangle =14=26, the perpendicular = 12 = p, and the sum of the sides = 28=*; to find the sides. Ans. The difference of the segments of the base made by the perpendicular is 4., or, in general terms, 10. Given the base of a triangle = 14 = 26, the perpendicular = 12 = p,... | |
 | Harvey Goodwin (bp. of Carlisle.) - 1847 - 136 σελίδες
...ABC, given the sum of the sides AC, BC ; the perpendicular from the vertex С upon the base AB; and the difference of the segments of the base made by the perpendicular ; find the sides of the triangle. 4. Given the vertical angle, the perpendicular let fall from the... | |
 | Elias Loomis - 1849 - 252 σελίδες
...the base of any triangle is to the sum of the two other sides, as the difference of the latter is to the difference of the segments of the base made by the perpendicular. PROPOSITION XXXII. THEOREM. The diagonal and side of a square have no common measure. Let ABCD be a... | |
 | Sir Henry Edward Landor Thuillier - 1851 - 826 σελίδες
...the base AD, will be to the sum of the other sides, AB, BD, as the difference of those sides, is to the difference of the segments of the base, made by the perpendicular BE ; viz : the difference between AJE and ED. Produce BD, till BG = AB the lesser side; and on B as... | |
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CE is equal to the difference of the segments of the base made by the perpendicular. 
