 | George Roberts Perkins - 1842 - 370 σελίδες
...Hence, the product will be Saab X 4:aaabb=l2aaaaabbb=l2asb3. Here we discover that the exponent of a, in the product, Is equal to the sum of the exponents of a in the factors ; likewise the exponent of b, in the product, is equal to the sum of the exponents... | |
 | Joseph Ray - 1848 - 250 σελίδες
...That the coefficient of any term is equal. to the product of the coefficients of its factors. 2d. That the exponent of any letter in the product is equal to the sum of its exponents in the two factors. 3d. That the product of like signs, gives plus in the product, and... | |
 | George Roberts Perkins - 1848 - 234 σελίδες
...by 4a362, will be, Saab X 4aaa66=12aaaaa666=12a663. From which we discover, that the exponent of a, in the product, is equal to the sum of the exponents of a in the factors ; likewise, the exponent of 6, in the product^ is equal to the sum of the exponents... | |
 | Joseph Ray - 1848 - 250 σελίδες
...That the coefficient of any term is equal to the product of the coefficients of its factors. 2d. That the exponent of any letter in the product is equal to the sum of its exponents in the two factors. 3d. That the product of like signs, gives plus in the product, and... | |
 | Joseph Ray - 1852 - 408 σελίδες
...That the coefficient of any term is equal to the product of the coefficients of its factors. 2d. That the exponent of any letter in the product is equal to the sum of its exponents in the two factors. 3 d. That the product of like signs gives plus in the product, and... | |
 | Horatio Nelson Robinson - 1863 - 432 σελίδες
...а'Ь' by a'b*. Since а*Ъ'= aaaa ЪЪЪ, and a*b'=aaa bb, we have • a>b'Xa'l>*=aaaabbbaaabb=a'bt. Hence, The exponent of any letter in the product is...is to be taken. In Algebra, however, a multiplier may be affected by either the plus or the minus sign ; and it is necessary to consider how the sign... | |
 | Joseph Ray - 1866 - 420 σελίδες
...MULTIPLICATION AND DIVISION OF QUANTITIES WITH FRACTIONAL EXPONENTS. , . It has beep shown (Art. 56) that the exponent of any letter in the product is equal to the sum of its exponents in the two factors. It will now .be shown that the lame rule applies when the exponents... | |
 | Joseph Ray - 1852 - 422 σελίδες
...That the coefficient of any term is equal to the product of the coefficients of its factors. 2d. That the exponent of any letter in the product is equal to the sum of its exponents in the two factors. 8 d. That the product of like signs gives plus in the product, and... | |
 | Horatio Nelson Robinson - 1868 - 430 σελίδες
...multiply a'l* by а'Ъ*. Since a'l' = aaaalbb, and a'l' = aaa Ы, we have a'l>"y(_a'b*=aaaaoolaaabb=:a'i'. Hence, The exponent of any letter in the product is...multiplicand and multiplier. 3d. The law of signs. Jn Arithmetic, multiplication is restricted to the simple process of repeating a number; and the only... | |
 | Elias Loomis - 1868 - 386 σελίδες
...which is obtained by adding together 3 and 2, the exponents of the common letter a. Hence we see that the exponent of any letter in the product is equal...of this letter in the multiplicand and multiplier. 59. Hence, for the multiplication of monomials, we have the following RULE. Multiply together the coefficients... | |
| |
That the exponent of any letter in the product is equal to the sum of its exponents in the two factors. 
