bu. pecks. gal. DRY MEASURE. gr. bu. P. wey. qr. bu. last. gr. bu. (1) 25 2 1 (2)25 3 1 (3) 72 3 6 (4)74 2 0 17 2 1 19 6 2 27 4 2 68 1 6 1. Bought 17 cwt. 2 qr. 15 lb., and sold 7 cwt. 3 qr. 16 lb. how much had I left? Ans. 9 cut. 2 gr. 27 lb. 2. A druggist, after disposing of 10 lb. 4 oz. 1 dr. 2 sc. 8 gr! from a cask which at first contained 15 lb.: I wish to know how much remains. Ans. 4lb. 7oz. 6dr. Osc. 12gr. 3. A gentleman divided 100 acres of land between his two sons; the eldest had for his share 64 acres, 1 rood, 15 poles : required the youngest son's share. Ans. 35a. 2r. 25p, 4. A person set out to travel to a certain place, distant 97 miles, and after he had gone 51 miles, 3 furlongs, 2 poles, and 3 yards, what distance was he from the place? 5. A piece of silk measures 54 37 yards, 3 quarters, and 2 nails: length. Ans. 45m. 4f. 37p. 2 yds. yards, and a piece of cloth required their difference in Ans. 16yds. Oqrs. 2n 6. A pipe of wine, which was leaky, was found to be 10 gallons, 3 quarts 1 pint deficient: required the quantity left. Ans. 115gal. Oqts. 1pt. 7. Two porter vats, one containing 27 butts, 1 hhd. 1 bar. 37 gallons, and the other 30 butts: required their difference. Ans. butt 1hhd. Obar 35gal. 8. Two pieces of building, one measuring 220 square yards, and the other 150 yards, 7 feet, 36 inches: required their difference in area. Ans. 69yds 1ft. 108 in. 9. Two reservoirs, out of one was dug 942 cubic yards, 16 feet, 174 inches, and out of the other 793 yards, 21 feet, 258 inches how much did the one exceed the other in size? : Ans. 148yds. 21ft. 1644in. 10. A was born at 2 o'clock in the afternoon on the 6th of April, 1837, and B on the 28th of January, at 5 o'clock in the morning, in 1842. How much does A's age exceed B's. allowing 30 days to a month. Ans. 4yrs. 9m. 21days 15hrs. COMPOUND MULTIPLICATION. BY COMPOUND MULTIPLICATION we find the value or amount of any given number of different denominations. CASE I.—When the given quantity does not exceed 12. RULE.-Multiply the price or compound quantity by the given number, beginning with the lowest denomination; divide this product by as many of this denomination as will make one of the next superior denomination; put down the remain-der, and carry the quotient to the product of the next denomination, and so on, to the end; and the result will be the value or amount required. EXAMPLES. 1. What is the value of 8 yards of cloth, at 15s. 4d. per 2. Required the weight of 4 hogsheads of sugar, each weighing 7 cwt. 2 qrs. 15 lb. 5. Required the value of 9 yards, at 17s. 6d. per yard. Ans. £7 17s. 101d. 6. What is the value of 7 yards, at 14s. 104d. per yard? 7. What is the value of 9 cwt., at £2 8. What is the value of 10 yards, at 9. What is the value of 11 yards, at 10. What is the value of 12 quarters per quarter? Ans. £5 4s. 11⁄2d. 15s. 4 d. per cwt? Ans. £24 18s. 4 d. 9s. 84d. per yard? Ans. £4 17s. 31d. 10s. 114d. per yard? Ans. £6 Os. 91d. oats, at 17s. 41d. Ans. £10 8s. 6d. of 11. What is the value of 12 cwt. at £1 12. Multiply 4 oz. 5 dwt. 12 gr. by 6. 4s. 9 d. per cwt. ? Ans. £14 17s. 6d. Ans. 2 lb. 1 oz. 13 dwt. 13. Multiply 1 cwt. 2 qr. 8 lb. by 12. Ans. 18 cwt. 3 qr. 12 lb. Ans. 21 lb. 5 oz. 7 dr. 2 sc. 10 gr. 14. Multiply 4 lb. 3 oz. 4 dr. 2 sc. 18 gr. by 5. 15. Multiply 12 yards, 2 feet, 6 inches by 8. Ans. 102 yds. 2 ft. 16. Multiply 3 barrels, 4 gallons, 3 quarts by 12. Ans. 37 bar. 21 gal. 17. Multiply 3 quarters, 4 bushels, 2 pecks by 9. Ans. 32 qrs. 2 pecks. 18. Multiply 7 square feet, 120 square inches by 7. Ans. 6 sq. yds. 120 sq. in. 19. Multiply 5 cubic feet, 150 cubic inches by 12. Ans. 2 yds. 7 ft. 72 in. 20. Multiply 7 weeks, 4 days, 6 hours by 9. Ans. 68 weeks, 3 days, 6 hours. CASE II.-When the given number exceeds 12, but not 144. RULE. Find two numbers whose product will make the given quantity; multiply the given price or compound quantity successively, or first by one of the numbers, and this product by the other number, and the last product will be the amount required. But if two numbers or component parts cannot be found to make the given quantity, find two whose product will approximate the nearest to it, and take as many times the given price as the product of the two numbers differs from the given quantity, which add to, or subtract from the the last product, as the case may require, and the last result will be the answer, as in example 2. EXAMPLES. 1. Required the value of 25 yards of cloth, at 17s. 6d. per yard. S. d. 2. What is the value of 29 yards, at 12s. 6d. per yard? 8. d. 4× 7+1=29 4. Required the value of 35 yards, at 10s. 8d. per yard. Ans. £18 13s. 4d. 5. Required the value of 46 cwt. at £2 6s. 8d. per cwt. Ans. £107 6s. 8d. 6. What is the value of 49 yards, at 15s. 44d. per yard? Ans. £37 13s. 4ld. 7. What is the value of 52 yards, at 16s. 4d. per yard? Ans. £42 9s. 4d 8. What is the value of 59 cwt. at £2 3s. 4d. per cwt? Ans. £127 16s. 8d. 9. What is the value of 74 cwt. at £1 4s. 54d. per cwt. Ans. £90 9s. Ild 10. Multiply 4 lb. 7 oz. 6 dwt. 4 gr. by 95. Ans. 437 lb. 10 oz. 5 dwts. 20 g 11. Multiply 4 yards, 2 feet, 6 inches by 107. grs. Ans. 517 yards, 0 feet, 6 inches. 12. What is the value of 145 yards, at 11s. 104. per yard? Ans. £86 Is. 101d CASE III-When the given number or quantity contains. three or more figures. RULE.-Multiply the given price or compound quantity by as many tens, less one, as the given number contains figures, and the last product by the first figure on the left of the given number; then multiply by the units, tens, hundreds, &c., and the sum of these products will be the amount or value required. N.B. The questions in Practice may be done by this rule EXAMPLES. 1. What is the value of 365 yards, at 12s. 4d. per yard? |